本文介绍了NSTimeInterval为可读的NSNumber的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
NSTimeInterval == double; (例如169.12345666663)
NSTimeInterval == double; (e.g. 169.12345666663)
如何舍入此双精度值,以便在点后只剩两个数字?
如果结果是NSNumber,则非常好。
How can I round up this double so that there are only 2 digits left after the "dot"?
It would be very good if the result is a NSNumber.
推荐答案
如果这是为了显示目的,请查看。
If this is for display purposes, take a look at NSNumberFormatter.
如果你真的想在计算中舍入双倍的某种原因,你可以使用标准的C round()
函数。
If you really want to round the double in your calculations for some reason, you can use the standard C round()
function.
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