将字符串位转换为字符串char，反之亦然，可以转换为ASCII C＃

问题描述

你好，

请你能帮我解决一下C＃中的代码将字符串转换为字符串字符串，反之亦然，可以用ASCII格式来表示

例如：

bitstring =00111111101101010011111101101111001111111110110110011111101101111

resultstring =？μ？o？Û？o

并将其反转......



如果最好的话，你可以更正我的代码吗？



我尝试了什么：



拳头：

hello,
Please can you help me about code in C# to converting string bit to string char or vice versa,can out to ASCII
for example:
bitstring ="0011111110110101001111110110111100111111110110110011111101101111"
resultstring ="?µ?o?Û?o"
and reversing its...

Can you correct my code if it is the best?

What I have tried:

fist:

string result = "";
            while (value.Length > 0)
            {   var first8 = value.Substring(0, 8);
                value = value.Substring(8);
                var number = Convert.ToInt64(first8, 2);
                result += (char)number;

second

second

string S = "";
            byte[] asciiBytes = Encoding.ASCII.GetBytes(value);
            for (int i = 0; i < asciiBytes.Length; i++)
                for (int j = 0; j < 8; j++)
                {
                    S += (asciiBytes[i] & 0x80) > 0 ? "1" : "0";
                    asciiBytes[i] <<= 1;
                }
            return S;

推荐答案

private string CharStringFromBitStringLittleEndian(string s)
    {
    StringBuilder sb = new StringBuilder(s.Length / 8 + 1);
    byte temp = 0;
    byte bit = 1;
    foreach (char c in s)
        {
        if (c == '1') temp |= bit;
        bit <<= 1;
        if (bit == 0)
            {
            sb.Append((char)temp);
            bit = 1;
            temp = 0;
            }
        }
    if (bit != 1) sb.Append((char)temp);
    return sb.ToString();
    }
private string CharStringFromBitStringBigEndian(string s)
    {
    StringBuilder sb = new StringBuilder(s.Length / 8 + 1);
    byte temp = 0;
    byte bit = 128;
    foreach (char c in s)
        {
        if (c == '1') temp |= bit;
        bit >>= 1;
        if (bit == 0)
            {
            sb.Append((char)temp);
            bit = 128;
            temp = 0;
            }
        }
    if (bit != 1) sb.Append((char)temp);
    return sb.ToString();
    }

int value = 219;
string binary = Convert.ToString(value, 2).PadLeft(8, '0');

2。）自制

2.) Self made

int value = 219;
StringBuilder sb = new StringBuilder(8);
while(value > 0)
{
	int mod= value % 2;
        if (mod == 0)
        {
        	sb.Insert(0, "0");
        }
	else
        {
        	sb.Insert(0, "1");
        }
        value /= 2;
}
string binary = sb.ToString().PadLeft(8, '0');

注意

注意，您正在使用Unicode，其中一个字符具有16位，而您的示例假设使用8位字符。

Note
Take care, you are working with Unicode for which a character has 16bit while your example assumes using 8 bit character.

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