问题描述
下面是代码片段，
int a = 1;
char b = (char) a;
System.out.println(b);
但我得到的是空输出.
int a = '1';
char b = (char) a;
System.out.println(b);
我将得到 1 作为我的输出.
I will get 1 as my output.
有人能解释一下吗?如果我想像第一个片段那样将 int 转换为 char，我应该怎么做?
Can somebody explain this? And if I want to convert an int to a char as in the first snippet, what should I do?
推荐答案
int a = 1;
char b = (char) a;
System.out.println(b);
将打印出带有 Unicode 代码点 1(标题开头的字符，不可打印；请参阅此表:C0 控件和基本拉丁语, 同 ASCII)
will print out the char with Unicode code point 1 (start-of-heading char, which isn't printable; see this table: C0 Controls and Basic Latin, same as ASCII)
int a = '1';
char b = (char) a;
System.out.println(b);
将打印出 Unicode 码位为 49 的字符(对应于 '1')
will print out the char with Unicode code point 49 (one corresponding to '1')
如果你想转换一个数字 (0-9)，你可以给它加上 48 并强制转换，或者类似 Character.forDigit(a, 10);.
If you want to convert a digit (0-9), you can add 48 to it and cast, or something like Character.forDigit(a, 10);.
如果要转换被视为 Unicode 代码点的 int，可以使用 Character.toChars(48) 例如.
If you want to convert an int seen as a Unicode code point, you can use Character.toChars(48) for example.
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