C＃转换对象为十进制

问题描述

我试图将对象转换为值 0.39999999999999997 来小数变量不失precision。

I'm trying to convert an object with the value 0.39999999999999997 to a decimal variable without losing the precision.

object d = 0.39999999999999997;

我尝试下面的方法。

I've tried the following methods.

decimal val1 = Convert.ToDecimal(d); // val1 = 0.4
object val2 = Convert.ChangeType(d, Type.GetType("System.Decimal")); // val2 = 0.4
decimal val3 = decimal.Parse(d.ToString()); // val3 = 0.4
decimal val4 = (Decimal) d; // val4 = 0.4

我知道这是不是与十进制数据类型不能够如下所示存储该值的问题。

I know the this is not a problem with the decimal data type not being able to store this value as illustrated below.

decimal val5 = 0.39999999999999997m; // val5 = 0.39999999999999997;

我如何将此对象转换为十进制不失precision？

How do I convert this object to decimal without losing the precision?

我使用的.NET Framework 3.5，如果该事项。

I'm using .NET Framework 3.5 if that matters.

推荐答案

我觉得这是code您寻找：

I think this is the code you looking for:

object d = 0.39999999999999997;
//Unbox value
double doubleVal = (double)d;

//Convert to string. R format specifier gives a string that can round-trip to an identical number.
//Without R ToString() result would be doubleAsString = "0.4"
string doubleAsString = doubleVal.ToString("R");

//Now that you have doubleAsString = "0.39999999999999997" parse it!
decimal decimalVal = decimal.Parse(doubleAsString);

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