问题描述
我有二维图像，其折线由：
I have binary image with polylines created with:
cv2.polylines(binaryImage,contours,1, (255,255,255))
我现在需要的是填充所有折线的有效方法。我还没有在opencv中找到这样的方法，但也许它存在。或者，也许我可以实现算法来完成这项工作（但快速 - 我有高清就绪图片）。请分享您的想法..
What I need now is effective method to fill all polylines. I haven't found such method in opencv, but maybe it exists. Alternatively, maybe I could implement algorithm to do the job (but fast one- I have HD ready pictures). Please share your thoughts..
推荐答案
我认为你要找的是，填充由一个区域限定的区域或更多的多边形。这是一个简单的片段，我生成一个四个点的轮廓，表示一个正方形的顶点，然后我用白色填充多边形。
I think what you are looking for is cv2.fillPoly, which fills the area bounded by one or more polygons. This is a simple snippet, I generate a contour of four points representing vertices of a square, then I fill the polygon with a white color.
import numpy as np
import cv2
contours = np.array( [ [50,50], [50,150], [150, 150], [150,50] ] )
img = np.zeros( (200,200) ) # create a single channel 200x200 pixel black image
cv2.fillPoly(img, pts =[contours], color=(255,255,255))
cv2.imshow(" ", img)
cv2.waitKey()
这篇关于用opencv python填充轮廓的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！