问题描述
你如何 grep 并只返回匹配的行?即结果中省略了路径/文件名.
How do you grep and only return the matching line? i.e. The path/filename is omitted from the results.
在这种情况下，我想查看当前目录中的所有 .bar 文件，搜索词 FOO
In this case I want to look in all .bar files in the current directory, searching for the term FOO
find . -name '*.bar' -exec grep -Hn FOO {} ;
推荐答案
无需查找.如果您只是在特定目录中寻找模式，这应该足够了:
No need to find. If you are just looking for a pattern within a specific directory, this should suffice:
grep -hn FOO /your/path/*.bar
其中-h是隐藏文件名的参数，来自man grep:
Where -h is the parameter to hide the filename, as from man grep:
-h, --no-filename
禁止输出文件名的前缀.这是默认的当只有一个文件(或只有标准输入)要搜索时.
Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search.
请注意，您正在使用
-H, --with-filename
打印每个匹配项的文件名.这是默认的，当有要搜索的文件不止一个.
Print the file name for each match. This is the default when there is more than one file to search.
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