不以"//"开头的行的Grep

If you're really hungup on using regular expressions then a simple one would look like (match start of string ^, any number of white space [[:space:]]*, exactly two backslashes /{2}, any number of any characters .*, followed by #include):grep -E "^[[:space:]]*/{2}.*#include" bar.txt 这篇关于不以"//"开头的行的Grep的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！