本文介绍了如何将图像从URL追加到FormData-Javascript的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我的小javascript代码:
This is my little javascript code:
<script>
var formData = new FormData();
URL = "view.php?fetchImageById=1";
formData.append("imageFile", ....);
formData.append("author","user");
formData.append("description","image");
x=new XMLHttpRequest();
x.open("POST","upload.php",true);
x.setRequestHeader("Content-type", "multipart/form-data");
x.setRequestHeader("Content-Length",formData.length);
x.send(formData);
</script>
我不知道如何将URL附加到formData.
I don't know how to append the URL to the formData.
推荐答案
您可以执行两个XMLHttpRequest()
;通过将responseType
设置为"blob"
,首先将GET
请求图像作为Blob
;然后将Blob
响应附加到POST
You could perform two XMLHttpRequest()
s; first GET
request image as a Blob
first by setting responseType
to "blob"
; then append Blob
response to FormData
at POST
var formData = new FormData();
URL = "view.php?fetchImageById=1";
var x;
var request = new XMLHttpRequest();
request.responseType = "blob";
request.onload = function() {
formData.append("imageFile", request.response);
formData.append("author","user");
formData.append("description","image");
x = new XMLHttpRequest();
x.open("POST","upload.php",true);
x.setRequestHeader("Content-type", "multipart/form-data");
x.setRequestHeader("Content-Length", formData.length);
x.send(formData);
}
request.open("GET", URL);
request.send();
这篇关于如何将图像从URL追加到FormData-Javascript的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!