如何读取ExpandaListView的getChild

本文介绍了如何读取ExpandaListView的getChild的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我在

的expandableListAdapter

 公共类ExpandableListAdapter扩展BaseExpandableListAdapter{
    私人上下文的背景下;
    私人列表＆LT;串GT; listdataheader;
    私人的HashMap＆LT;弦乐，产品＆GT; listdatachild;
    公共ExpandableListAdapter（上下文的背景下，ArrayList的＆LT;产品＆GT; FLIST）
    {
        HashMap的＆LT;弦乐，产品＆GT; listDataChild =新的HashMap＆LT;弦乐，产品＆GT;（）;
        对于（产品数据：FLIST）{
            listdatachild.put（data.Name，数据）;
        }        清单＆LT;串GT; listdataheader =新的ArrayList＆LT;串GT;（）;
        对于（产品数据：FLIST）{
            listdataheader.add（data.Name）;
        }        this.context =背景;
        this.listdataheader = listdataheader;
        this.listdatachild = listDataChild;
    }

我有在重写getChild，getChildrenCount方法的难度。
我有以下方法错误

 @Override
    public Object getChild(int groupPosition, int childPosition) {
        return this.listdatachild.get(this.listdataheader.get(groupPosition)).get(childPosition);
    }

and

@Override
public int getChildrenCount(int groupPosition) {
    // TODO Auto-generated method stub
    return this.listdatachild.get(this.listdataheader.get(groupPosition)).size();
}

解决方案

I think you messed up with your nested get and size, keep it simple!

I would have done something like this:

 public class ExpandableListAdapter extends BaseExpandableListAdapter{
    private Context context;
    private List<String> listdataheader = new ArrayList<String>();
    private HashMap<String, Products> listdatachild = new HashMap<String, Products>();
    public ExpandableListAdapter(Context context,ArrayList<Products> fList)
    {
        for (Products data : fList) {
            listdatachild.put(data.Name, data);
        }

        for (Products data: fList) {
            listdataheader.add(data.Name);
        }

        this.context=context;
    }

    @Override
    public Object getChild(int groupPosition, int childPosition) {
        return listdatachild.get(this.listdataheader.get(groupPosition);
    }

    @Override
    public int getChildrenCount(int groupPosition) {
    return listdatachild.size();
    }
}

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