问题描述
我必须删除大文件中第n个字符. Vi 会挂起这么大的文件.我知道 sed 中会有一些简单的命令可以做到这一点.但是，我发现很难理解 sed 脚本及其表达式.
I have to delete a character at nth position in a big file. Vi hangs for such a big file. I know there will be some simple command in sed to do so. But, I find it difficult to understand sed scripts and its expressions.
我拥有的文件内容如下:
The file I have has content like:
我必须删除多余的 ，即该文件中第 130405 个字符.我如何使用sed实现这一目标.
I have to delete that extra , which is 130405 th character in that file. How do I use sed to achieve this.
现在，我希望将所有双逗号替换为一个.该怎么办?
Now I wish to replace all aoocurances of double comma by a single one in-place. How can that be done?
推荐答案
sed -i's/.//130405'FILE
这将在位置( -i )上编辑文件( FILE )，删除位置 130405处的任何字符( .).
This edits the file (FILE) in place (-i), deleting any character (.) at position 130405
这篇关于如何使用sed删除文件中的第n个字符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！