从字符串中删除前缀

问题描述

试图从二进制数的左端去除0b1".

以下代码导致剥离所有二进制对象.(不好)

>>>bbn = '0b1000101110100010111010001' #转换后的 bin(2**24+**2^24/11)>>>aan=bbn.lstrip("0b1") #尝试一次剥离所有左端垃圾.>>>打印 aan #oops 都消失了.''

所以我分两步完成了 .lstrip():

>>>bbn = '0b1000101110100010111010001' # 同分数表达式>>>aan=bbn.lstrip("0b")# 以前做过这个.>>>打印 aan #Extra "1" 仍然存在.'1000101110100010111010001'>>>aan=aan.lstrip("1")# 如果一开始没有成功...>>>打印 aan #YES！'000101110100010111010001'

这是怎么回事?

再次感谢您通过一个简单的步骤解决了这个问题.(见我之前的问题)

解决方案

strip 系列将 arg 视为要删除的 set 字符.默认设置为所有空白字符".

你想要:

if strg.startswith("0b1"):strg = strg[3:]

Trying to strip the "0b1" from the left end of a binary number.

The following code results in stripping all of binary object. (not good)

>>> bbn = '0b1000101110100010111010001' #converted bin(2**24+**2^24/11)
>>> aan=bbn.lstrip("0b1")  #Try stripping all left-end junk at once.
>>> print aan    #oops all gone.
''

So I did the .lstrip() in two steps:

>>> bbn = '0b1000101110100010111010001' #    Same fraction expqansion
>>> aan=bbn.lstrip("0b")# Had done this before.
>>> print aan    #Extra "1" still there.
'1000101110100010111010001'
>>> aan=aan.lstrip("1")#  If at first you don't succeed...
>>> print aan    #YES!
'000101110100010111010001'

What's the deal?

Thanks again for solving this in one simple step. (see my previous question)

解决方案

The strip family treat the arg as a set of characters to be removed. The default set is "all whitespace characters".

You want:

if strg.startswith("0b1"):
   strg = strg[3:]

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