从Firestore动态删除数据

问题描述

我正在与React&Redux&Firestore，我知道如何删除/更新/添加等.但是当我有2个带有动态字段的子集合时，找不到任何解决方案来删除它.

I'm building a project with React & Redux & Firestore, I know how to delete/update/add etc..But when I have 2 subcollections with dynamic field, I couldn't find any solution to delete it.

如果看图片，我有表ID和用户ID，但字段是0、1、2等.

If you look at the picture, I have the table ID and user ID, but the fields are 0, 1, 2 and so on.

如何从tableGuests中删除字段?也许结构不好，可能会更好?

How can I delete a field from tableGuests?Maybe the structure is not good and could be better?

guests>用户ID> userTables>表ID> tableGuests，它是一个数组.

guests > user id > userTables > table id > tableGuests which is an array.

推荐答案

文档中没有明确的方法来说明如何从数组中弹出项目.我会这样做:

There is no clear way in the docs that explains how to pop an item from an array.I would do this:

1. 使用 const data = firestore().collection('userTables').doc(ID).get();
来获取表数据
2. 使用该数据获取数组的当前状态 const array = data.get('tableGuests');
3. 使用不包含要删除的项目的新数组更新文档(在本例中为最后一个) firestore().collection('userTables').doc(ID).update({tableGuests:array.slice(0，array.length-1)});

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