如何使用java代码在windows中打开应用程序(任务管理器->应用程序选项卡内容)

问题描述

下面的一个用于从windows获取进程列表

Below one is used for get list of processes from the windows

       Process proc = Runtime.getRuntime().exec ("tasklist.exe");

但我想获取应用程序标签内容本身我需要一个解决方案

But I want to get the application tab content itselfi need a solution for this

 Process proc = Runtime.getRuntime().exec ( ? ? ?);

推荐答案

我正在尝试给出答案，即使帖子已经超过一年了.

I am trying to give the answer, even if the post is already more than one year old.

尝试使用以下代码片段:

Try with the following code snippet:

private static final String STR_MATCH = "My Java Application";
String strProcess;
BufferedReader input = null;

try {
    if(System.getProperty("os.name").startsWith("Windows")) {
        Process p = Runtime.getRuntime().exec(System.getenv("windir") + "\\system32\\" + "tasklist.exe /v /FI \"STATUS eq RUNNING\" /FI \"imagename eq javaw.exe\"");
        input = new BufferedReader(new InputStreamReader(p.getInputStream()));

        while((strProcess = input.readLine()) != null) {
            if(strProcess.contains(STR_MATCH))
                /* lot of code here */
        }

        // Close resources
        input.close();
}
catch(IOEXception ioe) {
    /* handle exception */
}

这里需要注意的是获取Process p的方式，即:

The thing to notice here is the way used to get the Process p, i.e.:

Process p = Runtime.getRuntime().exec(System.getenv("windir") + "\\system32\\" + "tasklist.exe /v /FI \"STATUS eq RUNNING\" /FI \"imagename eq javaw.exe\"");

调用 tasklist.exe 时添加的过滤器 /FI "STATUS eq RUNNING"/FI "imagename eq javaw.exe" 允许获取更多相关信息到进程 javaw.exe，包括窗口/应用程序名称.

The filter /FI "STATUS eq RUNNING" /FI "imagename eq javaw.exe" that has been added when invoking tasklist.exe allows to get more information related to the process javaw.exe, including the Window/Application name.

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