如何在迭代集合时安全地从集合中删除其他元素

问题描述

我正在遍历一个JRE Collection ，该集合强制执行快速失败迭代器概念，因此将抛出 ConcurrentModificationException 如果在迭代时修改了 Collection ，而不是使用 Iterator.remove（）方法。但是，如果对象满足条件，则需要删除该对象的逻辑伙伴。从而阻止伙伴也被处理。我怎样才能做到这一点？

I'm iterating over a JRE Collection which enforces the fail-fast iterator concept, and thus will throw a ConcurrentModificationException if the Collection is modified while iterating, other than by using the Iterator.remove() method . However, I need to remove an object's "logical partner" if the object meets a condition. Thus preventing the partner from also being processed. How can I do that? Perhaps by using better collection type for this purpose?

示例。

myCollection<BusinessObject>

for (BusinessObject anObject : myCollection)
{
  if (someConditionIsTrue)
  {
    myCollection.remove(anObjectsPartner); // throws ConcurrentModificationException
  }
}

谢谢。

推荐答案

您要从列表中删除一项，然后继续在同一列表中进行迭代。您可以实施两步解决方案吗？在步骤1中，将要删除的项目收集到临时集合中，在步骤2中，在识别出它们之后将其删除？

You want to remove an item from a list and continue to iterate on the same list. Can you implement a two-step solution where in step 1 you collect the items to be removed in an interim collection and in step 2 remove them after identifying them?

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