本文介绍了重写XML序列化方法的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有麻烦试图自定义的DateTime变量是连载于我的对象的方式。我想这是输出2011-09-26T13:00:00Z但是当我重写GetObjectData使用()函数,因为我相信是这样做的方式,没有XML数据输出它们。
[DataContract(命名空间=)]
[XmlRootAttribute(命名空间=http://www.w3.org/2005/Atom的ElementName =饲料)
公共类克卡
{
[XmlNamespaceDeclarations]
公共XmlSerializerNamespaces _xsns =新XmlSerializerNamespaces();
[的XmlElement(的ElementName =条目)]
公文集< MMU.Calendar.gCalEvent>项目=新集合< MMU.Calendar.gCalEvent>();
/ *一些其他元素* /
}
公共类gCalEvent
{
[的XmlElement(命名空间=http://schemas.google.com/g/2005)
公共gdEvent当=新gdEvent();
/ *一些其他元素* /
}
公共类gdEvent:ISerializable的
{
[XmlAttribute(AttributeName的=startTime时)]
私营的DateTime _startTime;
[XmlAttribute(AttributeName的=endTime的)]
私营的DateTime _endTime;
公共gdEvent(日期时间的startTime,日期时间endTime的)
{
_startTime = startTime时;
_endTime = endTime的;
}
公共gdEvent()
{
_startTime = DateTime.MinValue;
_endTime = DateTime.MinValue;
}
[SecurityPermissionAttribute(SecurityAction.Demand,SerializationFormatter =真)
公共虚拟无效GetObjectData使用(SerializationInfo中的信息,的StreamingContext上下文)
{
//需要在格式2011-09-26T13:00:00Z
//如果(_startTime!= DateTime.MinValue)
info.AddValue(startTime时,_startTime.ToString(YYYY-MM-DDTHH:毫米:SSZ);
//如果(_endTime!= DateTime.MinValue)
info.AddValue(endTime的,_endTime.ToString(YYYY-MM-DDTHH:毫米:SSZ));
}
}
克卡日历=新克卡();
日历= readSwsS preadsheet(urlToCall);
流=新的MemoryStream();
XmlSerializer的序列化=新的XmlSerializer(typeof运算(兆千卡));
serializer.Serialize(流,日历);
stream.Seek(0,SeekOrigin.Begin);
流的结果=新的MemoryStream();
WebOperationContext.Current.OutgoingResponse.ContentType =为text / xml;
返回流;
我也想看看这个信息了,但似乎有很多关于自定义序列化到文件,而不是XML ...
解决方案 我已经从@craighawker建议调用set()方法的日期时间时,日期时间格式化成字符串
。似乎是最简单的方法,但我想实现它使用的IXmlSerializable在一些点在未来做更多的强大的东西的正确方法
公共类gdEvent
{
[XmlAttribute(AttributeName的=startTime时)]
私人字符串m_startTimeOutput;
私营的DateTime m_startTime; //格式2011-11-02T09:00:00Z
[XmlAttribute(AttributeName的=endTime的)]
私人字符串m_endTimeOutput;
私营的DateTime m_endTime; // 2011-11-02T10:00:00Z
公开日期时间的startTime
{
得到
{
返回m_startTime;
}
组
{
m_startTime =价值;
m_startTimeOutput = m_startTime.ToString(YYYY-MM-DDTHH:毫米:SSZ);
}
}
公开日期时间endTime的
{
得到
{
返回m_endTime;
}
组
{
m_endTime =价值;
m_endTimeOutput = m_endTime.ToString(YYYY-MM-DDTHH:毫米:SSZ);
}
}
I'm having trouble trying to customize the way DateTime variables are serialized in my objects. I want it to be output as 2011-09-26T13:00:00Z but when I override the GetObjectData() function as I believe is the way to do this, no XML data is output for them at all.
[DataContract(Namespace = "")]
[XmlRootAttribute(Namespace = "http://www.w3.org/2005/Atom", ElementName = "feed")]
public class GCal
{
[XmlNamespaceDeclarations]
public XmlSerializerNamespaces _xsns = new XmlSerializerNamespaces();
[XmlElement(ElementName = "entry")]
public Collection<MMU.Calendar.gCalEvent> items = new Collection<MMU.Calendar.gCalEvent>();
/*some other elements*/
}
public class gCalEvent
{
[XmlElement(Namespace = "http://schemas.google.com/g/2005")]
public gdEvent when = new gdEvent();
/*some other elements*/
}
public class gdEvent : ISerializable
{
[XmlAttribute(AttributeName = "startTime")]
private DateTime _startTime;
[XmlAttribute(AttributeName = "endTime")]
private DateTime _endTime;
public gdEvent(DateTime startTime, DateTime endTime)
{
_startTime = startTime;
_endTime = endTime;
}
public gdEvent()
{
_startTime = DateTime.MinValue;
_endTime = DateTime.MinValue;
}
[SecurityPermissionAttribute(SecurityAction.Demand, SerializationFormatter = true)]
public virtual void GetObjectData(SerializationInfo info, StreamingContext context)
{
//needs to be in the format 2011-09-26T13:00:00Z
//if (_startTime != DateTime.MinValue)
info.AddValue("startTime", _startTime.ToString("yyyy-MM-ddTHH:mm:ssZ");
//if (_endTime != DateTime.MinValue)
info.AddValue("endTime", _endTime.ToString("yyyy-MM-ddTHH:mm:ssZ"));
}
}
GCal calendar = new GCal();
calendar = readSwsSpreadsheet(urlToCall);
stream = new MemoryStream();
XmlSerializer serializer = new XmlSerializer(typeof(GCal));
serializer.Serialize(stream, calendar);
stream.Seek(0, SeekOrigin.Begin);
Stream results = new MemoryStream();
WebOperationContext.Current.OutgoingResponse.ContentType = "text/xml";
return stream;
I have tried to look this info up but there seems to be a lot about custom serializing to files but not to XML...
解决方案
I had a suggestion from @craighawker to format the DateTime into a string when calling a set() method for the DateTime. Seemed the simplest method although I would like to implement it the proper way using IXMLSerializable at some point in the future to do more powerful things
public class gdEvent
{
[XmlAttribute(AttributeName = "startTime")]
private string m_startTimeOutput;
private DateTime m_startTime; //format 2011-11-02T09:00:00Z
[XmlAttribute(AttributeName = "endTime")]
private string m_endTimeOutput;
private DateTime m_endTime; //2011-11-02T10:00:00Z
public DateTime startTime
{
get
{
return m_startTime;
}
set
{
m_startTime = value;
m_startTimeOutput = m_startTime.ToString("yyyy-MM-ddTHH:mm:ssZ");
}
}
public DateTime endTime
{
get
{
return m_endTime;
}
set
{
m_endTime = value;
m_endTimeOutput = m_endTime.ToString("yyyy-MM-ddTHH:mm:ssZ");
}
}
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08-28 03:45