`变量不在范围内`在一个简单的函数中

问题描述

考虑下一段代码 -

  pvp :: Board-> Int-> IO（）
 pvp board player = do 
 player1choice<  -  prompt $（Player++（show（player + 1））++，轮到你了：）
 
 if player == 0 
然后让newboard =（把棋盘X（读取player1choice））放到新棋盘
中else newboard =（把棋盘O（读取player1choice））放到新棋盘
 
案例
的新案例Nothing  - > putStrLn无效移动。 
只需登上' - > putStrLn有效移动。 
  

对于 case newboard of ，我得到 error：变量不在范围内：newboard :: Maybe a0 。这是什么原因？

解决方案

由于我没有整个haskell文件，我只能给出一个有教养的猜测 - 但你是如果.. then .. else 表达式

这应该是正确的假设 put 返回一个新的 Board - 并且与 State ：

  pvp :: Board  - > Int  - > IO（）
 pvp board player = do 
 player1choice<  -  prompt $（Player++（show（player + 1））++，轮到你了：）
让newboard = if玩家== 0 
然后把棋盘X（读取player1choice）
放到棋盘上O（读取player1choice）
 case newboard 
 Nothing  - >做
 putStrLn无效移动。 
  -  playGame b 
只需登上' - > putStrLn有效移动。 
  





注意（与您的问题无关）

你应该避免 read 如果有人输入了一个无效的输入，它会使你的程序崩溃 - 比如说你期望一些数字的字母。更好地使用

Consider the next piece of code -

pvp::Board->Int-> IO ()
pvp board player = do
  player1choice <- prompt $ ("Player " ++  (show (player + 1)) ++ ", it's your turn:")

  if player == 0
    then let newboard = (put board X (read player1choice)) in newboard
    else let newboard = (put board O (read player1choice)) in newboard

  case newboard of
    Nothing -> putStrLn "Invalid move."
    Just board' -> putStrLn "Valid move."

For case newboard of, i get error: Variable not in scope: newboard :: Maybe a0. whats the reason for this?

解决方案

Since I have not the whole haskell file I can only give an educated guess - but you are having newboard only in scope of your if .. then .. else expression

This should be correct assuming put is returning a new Board - and has nothing to do with State:

pvp :: Board -> Int -> IO ()
pvp board player = do
  player1choice <- prompt $ ("Player " ++  (show (player + 1)) ++ ", it's your turn:")
  let newboard = if player == 0
                   then put board X (read player1choice)
                   else put board O (read player1choice)
  case newboard of
      Nothing -> do
        putStrLn "Invalid move."
        -- playGame b
      Just board' -> putStrLn "Valid move."

Note (unrelated to your problem)

You should avoid read it will crash your program if someone enters an invalid input - say a letter where you expect something numeric. better use readMaybe

这篇关于`变量不在范围内`在一个简单的函数中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！