Framework的APIRequestFactory生成文件上

Framework的APIRequestFactory生成文件上

本文介绍了如何使用Django REST Framework的APIRequestFactory生成文件上传(测试)请求?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我已经开发了一个API(Python 3.5,Django 1.10,DRF 3.4.2),当我从用户界面请求视频文件时,该视频文件会上传到我的媒体路径中。那部分工作正常。我尝试为此功能编写测试,但无法使其成功运行。

I have developed an API (Python 3.5, Django 1.10, DRF 3.4.2) that uploads a video file to my media path when I request it from my UI. That part is working fine. I try to write a test for this feature but cannot get it to run successfully.

#views.py

import os
from rest_framework import views, parsers, response
from django.conf import settings


class FileUploadView(views.APIView):
    parser_classes = (parsers.FileUploadParser,)
    def put(self, request, filename):
        file = request.data['file']
        handle_uploaded_file(file, filename)
        return response.Response(status=204)

def handle_uploaded_file(file, filename):
    dir_name = settings.MEDIA_ROOT + '/scene/' + filename + '/cam1'
    new_filename = 'orig.mp4'
    if not os.path.exists(dir_name):
        os.makedirs(dir_name)
    file_path = os.path.join(dir_name, new_filename)
    with open(file_path, 'wb+') as destination:
        for chunk in file.chunks():
            destination.write(chunk)

#test.py

import tempfile
import os
from django.test import TestCase
from django.conf import settings
from django.core.files import File
from django.core.files.uploadedfile import SimpleUploadedFile
from rest_framework.test import APIRequestFactory
from myapp.views import FileUploadView


class UploadVideoTestCase(TestCase):
    def setUp(self):
        settings.MEDIA_ROOT = tempfile.mkdtemp(suffix=None, prefix=None, dir=None)

    def test_video_uploaded(self):
        """Video uploaded"""
        filename = 'vid'
        file = File(open('media/testfiles/vid.mp4', 'rb'))
        uploaded_file = SimpleUploadedFile(filename, file.read(), 'video')
        factory = APIRequestFactory()
        request = factory.put('file_upload/'+filename,
            {'file': uploaded_file}, format='multipart')
        view = FileUploadView.as_view()
        response = view(request, filename)
        print(response)

        dir_name = settings.MEDIA_ROOT + '/scene/' + filename + '/cam1'
        new_filename = 'orig.mp4'
        file_path = os.path.join(dir_name, new_filename)
        self.assertTrue(os.path.exists(file_path))

在此测试中,我需要使用现有的视频文件( media / testfiles / vid.mp4)并上传它,因为我需要在之后的视频数据:这就是为什么我使用 mkdtemp 重置 MEDIA_ROOT 的原因。

In this test, I need to use an existing video file ('media/testfiles/vid.mp4') and upload it since I need to test some processings on the video data after: that's why I reset the MEDIA_ROOT using mkdtemp.

由于文件未上传,因此测试失败。当我打印请求 views.py def中放置 $ c>我得到< rest_framework.request.Request对象位于0x10f25f048> ,当我打印 request.data 时,什么都没得到。但是,如果我在视图中删除 FileUploadParser 并使用 request = factory.put('file_upload /'+ filename,{'filename':filename} ,在我的测试中为format = multipart),我得到< QueryDict:{'filename':['vid']}> 当我打印 request.data

The test fails since the file is not uploaded. In the def put of my views.py, when I print request I get <rest_framework.request.Request object at 0x10f25f048> and when I print request.data I get nothing. But if I remove the FileUploadParser in my view and use request = factory.put('file_upload/' + filename, {'filename': filename}, format="multipart") in my test, I get <QueryDict: {'filename': ['vid']}> when I print request.data.

所以我的结论是我用 APIRequestFactory 不正确。 FileUploadParser 无法从其中检索原始文件。

So my conclusion is that the request I generate with APIRequestFactory is incorrect. The FileUploadParseris not able to retrieve the raw file from it.

因此,我的问题是:如何使用Django REST Framework的APIRequestFactory生成文件上传(测试)请求?

几个人在SO上提出了与此问题类似的问题,但我没有成功

Several people have asked questions close to this one on SO but I had no success with the proposed answers.

在此问题上的任何帮助将不胜感激!

Any help on that matter will be much appreciated!

推荐答案

现在可以了!从APIRequestFactory切换到APIClient,我设法运行了我的测试。

It's alright now! Switching from APIRequestFactory to APIClient, I managed to have my test running.

我的新test.py:

My new test.py:

import os
import tempfile
from django.conf import settings
from django.core.files import File
from django.core.files.uploadedfile import SimpleUploadedFile
from django.urls import reverse
from rest_framework.test import APITestCase, APIClient
from django.contrib.auth.models import User

class UploadVideoTestCase(APITestCase):
    def setUp(self):
        settings.MEDIA_ROOT = tempfile.mkdtemp()
        User.objects.create_user('michel')

    def test_video_uploaded(self):
        """Video uploaded"""
        filename = 'vid'
        file = File(open('media/testfiles/vid.mp4', 'rb'))
        uploaded_file = SimpleUploadedFile(filename, file.read(),
            content_type='multipart/form-data')
        client = APIClient()
        user = User.objects.get(username='michel')
        client.force_authenticate(user=user)
        url = reverse('file_upload:upload_view', kwargs={'filename': filename})
        client.put(url, {'file': uploaded_file}, format='multipart')
        dir_name = settings.MEDIA_ROOT + '/scene/' + filename + '/cam1'
        new_filename = 'orig.mp4'
        file_path = os.path.join(dir_name, new_filename)
        self.assertTrue(os.path.exists(file_path))

这篇关于如何使用Django REST Framework的APIRequestFactory生成文件上传(测试)请求?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-27 20:43