添加的EditText来警告对话框。

问题描述

我有以下的code表示创建警报对话框，我加了两个编辑文本，但一旦我运行的应用程序的的EditText内的值不会retrived和我的应用程序崩溃与NullPointerException异常：

在code是：

  AlertDialog.Builder警报=新AlertDialog.Builder（本）;
        LayoutInflater充气= this.getLayoutInflater（）;
        最后的EditText usernameInput =（EditText上）findViewById（R.id.dialogusername）;
        最后的EditText passwordInput =（EditText上）findViewById（R.id.dialogpassword）;
        alert.setView（inflater.inflate（R.layout.dialog，NULL））;
        alert.setTitle（请输入密码）;
        alert.setMessage（请输入密码，删除应用程序：）;
        alert.setPositiveButton（OK，新DialogInterface.OnClickListener（）{
        公共无效的onClick（DialogInterface对话，诠释whichButton）{
            //提供用户谨慎卸载前
            //这里还应该补充的是要读的密码AsyncTask的，一旦其检查密码是正确的应用程序将被删除
            值1 = usernameInput.getText（）的toString（）。
            值2 = passwordInput.getText（）的toString（）。
            如果（value1.equals（空）及和放大器; value2.equals（空））
            {Toast.makeText（背景下，输入用户名和密码，Toast.LENGTH_SHORT）.show（）;}
         }
        }）;
        }）;
        alert.show（）;
 

解决方案

谢谢你们在回答我的问题你的贡献，我觉得我得到了我张贴的问题的解决方案上面是：

  AlertDialog.Builder警报=新AlertDialog.Builder（MyFeedActivity.this）;
        LayoutInflater充气= MyFeedActivity.this.getLayoutInflater（）;
        //这是我做过什么，以增加布局的警告对话框
        查看布局= inflater.inflate（R.layout.dialog，NULL）;
        alert.setView（布局）;
        最后的EditText usernameInput =（EditText上）layout.findViewById（R.id.dialogusername）;
        最后的EditText passwordInput =（EditText上）layout.findViewById（R.id.dialogpassword）;
 

和我想的问题是，我不能得到EidtText警告对话框内，而是由上面code做的每一件事只是罚款和我在一起。

I have the following code that create alert dialog and I added two edit text to it but once I run the app the values within the EditText won't be retrived and my app crash with NullPointerException:

the code is:

AlertDialog.Builder alert = new AlertDialog.Builder(this);
        LayoutInflater inflater=this.getLayoutInflater();
        final EditText usernameInput=(EditText)findViewById(R.id.dialogusername);
        final EditText passwordInput=(EditText)findViewById(R.id.dialogpassword);
        alert.setView(inflater.inflate(R.layout.dialog,null));
        alert.setTitle("Enter Password");
        alert.setMessage("Enter password to remove the app:");
        alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {
            //provide user with caution before uninstalling
            //also here should be added a AsyncTask that going to read the password and once its checked the password is correct the app will be removed
            value1=usernameInput.getText().toString();
            value2=passwordInput.getText().toString();
            if(value1.equals(null)&&value2.equals(null))
            {Toast.makeText(context, "Enter username and password", Toast.LENGTH_SHORT).show();}
         }
        });
        });
        alert.show();

解决方案

Thanks guys for your contributions in answering my question, and I think I got the solution for the problem that I posted above which is:

AlertDialog.Builder alert = new AlertDialog.Builder(MyFeedActivity.this);
        LayoutInflater inflater=MyFeedActivity.this.getLayoutInflater();
        //this is what I did to added the layout to the alert dialog
        View layout=inflater.inflate(R.layout.dialog,null);
        alert.setView(layout);
        final EditText usernameInput=(EditText)layout.findViewById(R.id.dialogusername);
        final EditText passwordInput=(EditText)layout.findViewById(R.id.dialogpassword);

and I think the problem was that I cannot get the EidtText within the alert dialog, but by doing it by the above code every thing works just fine with me.

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