要显示与QUOT;装载.....＆QUOT;在PHP页面

问题描述

我开发一个网页中，需要下列功能的PHP：1.当用户点击表示感谢，应以改变完成！。2.同时，我想打电话给在indexController的动作。3.在这个时候，我想显示加载......4.当前页面有大量的动态内容，也应该不会改变。

I am developing a web-page in PHP that needs following functionality:1. When User click on "Say Thanks" it should be changed with "Done!".2. At the same time I want to call an action in indexController.3. At this time I want to show "loading...."4. The current page has a lot of dynamic contents that should also not change.

请建议我应该怎么做才能完成上述任务......

Please suggest me what should I do to complete above tasks......

推荐答案

我想你需要一个AJAX调用。我通常做的装载意见和这样的，当你preSS更多。就我而言，有一个空的div和＆LT; A＆gt;在链接的评论视图（带有单独行动，OFC）标记。然后我使用jQuery的AJAX魔法：

I figure you need an AJAX call. I usually do that for loading comments and such when you press "more". In my case, there's an empty div and an <a> tag with the link to the comments view (with a separate action, ofc). Then I use jQuery for the AJAX magic:

$(function() {
    $("a.CommentsListBtn").click(function() {
        var tmpHref = $(this).attr("href");
        var tmpLayer = $(this).parent().children("div.CommentsList");
        tmpLayer.load(tmpHref, function() {
            tmpLayer.stop().slideDown("medium");
        });
        return false;
    });
});

我希望这有助于。

I hope this helps.

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