通过多维数组和打印循环 | 通过多维数组和打印循环

本文介绍了通过多维数组和打印循环的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有，我想拉某些信息和使用PHP / HTML（即游戏ID，等级）它的输出数组。我有基础知识之后，我虽然只得到从输出的第一阵列中的信息。我知道，循环正是我需要做的，虽然我不完全知道如何在同一时间返回多个记录。有些是在一个阵列中的信息可能不会在其他的，你可以看到没有[信息]中的第一个。

下面是我的code：

 ＆LT; PHP$复习= $显象＆GT; API（'/源'）;    函数D（$ D）{
        呼应'＆LT; pre＆GT;';
        的print_r（$ D）;
        呼应'＆LT; / pre＆GT;';
    }    D（$检讨[数据] [0] [游戏]）;
    D（$检讨[数据] [0] [游戏] [评分]）;
？＆GT;

这是输出：

 阵列（[数据] =＆GT;数组（[0] =＆GT;数组（[ID] =＆GT; 2010_1110 [从] =＆GT;阵列（[名称] =＆GT ; Pebkac [ID] =＆GT; 11001010）[游戏] =＆GT;数组（[ID] =＆GT; 2112 [名] =＆gt;新建游戏[评分] =＆GT;数组（[动作] =＆GT; 9显卡] =→10））[评论] =＆GT;数组（[数据] =＆GT;数组（[0] =＆GT;数组（[ID] =＆GT; 2010_1111 [从] =＆GT;阵列（[名称] = ＆gt;我的朋友[ID] =＆GT; 10100110）[消息] =＆GT;您好[CREATED_TIME] =方式＆gt;下午8:00）））））[分页] =＆GT;阵列（[previous] =＆GT;为url1 [下一页] =＆GT; URL2））阵列（[数据] =＆GT;数组（[1] =＆GT;数组（[ID] =＆GT; 2010_1112 [从] =＆GT;阵列（[名称] =＆GT; Pebkac [ID] =＆GT; 11001010）[游戏] =＆GT;数组（[ID] =＆GT; 5050 [名] =＆GT;另一场比赛[评分] =＆GT;数组（[动作] =＆GT; 8 [显卡] =＆GT; 8））[资讯] =＆GT [CREATED_TIME] =＆GT;下午8时59分[拥有] =＆GT;数组（[数据] =＆GT;数组（[0] =＆GT;数组（[ID] =＆GT; 20100112 [名] =＆GT;朋友二）））[评论] =＆GT;数组（[数据] =＆GT;数组（[0] =＆GT;数组（[ID] =＆GT; 2010_1113 [从] =＆GT;阵列（[名称] =＆gt;我的朋友[ID] =＆GT; 10100110）[消息] =＆GT;您好[CREATED_TIME] =方式＆gt;下午9:00）））））

解决方案

根据你想要做什么，你可以做一个嵌套的循环，或者如果你拥有的维数n，您可以递归调用的函数，直到结果不再是一个数组。事情是这样的：

 函数printNode（$节点）{
    的foreach（$节点作为$ nodeKey =＆GT; $的nodeValue）{
        如果（is_array（$的nodeValue））{
            printNode（$的nodeValue）;
        }其他{
            打印$的nodeValue;
        }
    }
}

I have an array that I would like to pull certain information from and output it using php/html (i.e. game, id, rating). I have the basics down, although I only get the information from the first array in the output. I know that looping is what I need to do, although I'm not exactly sure how to return more than one record at a time. Some of the information that is in one array may not be in the other, as you can see there is no [info] in the first one.

Here's my code:

<?php

$review = $developer->api('/source');

    function d($d){
        echo '<pre>';
        print_r($d);
        echo '</pre>';
    }

    d($review[data][0][game]);
    d($review[data][0][game][rating]);
?>

This is the output:

Array( [data] => Array ( [0] => Array ( [id] => 2010_1110 [from] => Array ( [name] => Pebkac [id] => 11001010  ) [game] => Array ( [id] => 2112 [name] => New Game [rating] => Array ( [action] => 9 [graphics] => 10 ) ) [comments] => Array ( [data] => Array ( [0] => Array ( [id] => 2010_1111 [from] => Array ( [name] => My Friend  [id] => 10100110 ) [message] => hi there. [created_time] => 8:00 P.M. ) ) ) ) )

[paging] => Array ( [previous] => url1 [next] => url2 ))

Array( [data] => Array ( [1] => Array ( [id] => 2010_1112 [from] => Array ( [name] => Pebkac [id] => 11001010  ) [game] => Array ( [id] => 5050 [name] => Another Game [rating] => Array ( [action] => 8 [graphics] => 8 ) ) [info] => [created_time] => 8:59 P.M. [owns] => Array ( [data] => Array ( [0] => Array ( [id] => 20100112   [name] => Friend Two ) ) ) [comments] => Array ( [data] => Array ( [0] => Array ( [id] => 2010_1113 [from] => Array ( [name] => My Friend  [id] => 10100110 ) [message] => hi there. [created_time] => 9:00 P.M. ) ) ) ) )

解决方案

Depending on what you want to do, you can either do a nested for loop or if you have n number of dimensions, you can recursively call your function until the result is no longer an array. Something like this:

function printNode($node) {
    foreach ($node as $nodeKey => $nodeValue) {
        if (is_array($nodeValue)) {
            printNode($nodeValue);
        } else {
            print $nodeValue;
        }
    }
}

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