mysqli_fetch_assoc()期望参数1为mysqli_result，布尔值在

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问题描述

<?php
require_once("connect.php");

$login1 = $_POST['email'];
$password1 = $_POST['password'];
$select = "SELECT id FROM loginregistration WHERE login ='$login1', password   ='$password1'";
$sql = mysqli_query($con,$select);
$row = mysqli_fetch_assoc($sql);
?>`

我的mysqli_query似乎不起作用，我该怎么办?

it seems that my mysqli_query doesn't work ,what should i do?

推荐答案

在密码附近的查询中使用AND插入逗号(，)，这就是查询返回false并抛出该错误的原因

use AND insted of comma (,) in query near password that's why query returning false and throw that error

$select = "SELECT id FROM loginregistration WHERE login ='".$login1."' and password ='".$password1."'";

更新1

如果查询失败，则返回false.所以你可以使用mysqli_error($ con);知道错误

if query fail it return false . so you can use mysqli_error($con); to know the error

    <?php
    require_once("connect.php");

    $login1 = $_POST['email'];
    $password1 = $_POST['password'];
    $select = "SELECT id FROM loginregistration WHERE login ='".$login1."' AND password   ='".$password1."'";
    $sql = mysqli_query($con,$select);

    if($sql === FALSE) {
        die(mysqli_error($con)); // better error handling
    }

    $row = mysqli_fetch_assoc($sql);
    ?>

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