在PHP中读取多个文本文件的内容并打印出特定的行

问题描述

我们有300多个txt文件，其中基本上是电子邮件的副本，每个txt文件都具有以下格式:

We have 300+ txt files, of which are basically replicates of an email, each txt file has the following format:

To: [email protected]
Subject: blabla
From: [email protected]
Message: Hello World!

目的是编写一个PHP脚本，该脚本会爬网每个文件(所有文件都位于同一目录中)，并在发件人"字段中打印出每个唯一"电子邮件地址的列表.这个概念很简单.

The aim is to write a PHP script, which crawls through each file (all located within the same directory), and prints out a list of each 'unique' email address in the from field. The concept is very easy.

有人可以在这里向我指出正确的方向吗?到目前为止，我已经设法使我的PHP脚本读取目录中所有文件的内容并输出结果:

Can anyone point me in the right direction here? So far, I have managed to get my PHP script to read the contents of all of the files within the directory and output the result:

<?php
$directory = "emails/";
$dir = opendir($directory);
while (($file = readdir($dir)) !== false) {
  $filename = $directory . $file;
  $type = filetype($filename);
  if ($type == 'file') {
     $contents = file_get_contents($filename);
     $items = explode('/n', $contents);
     echo '<table width="500" border="1" cellpadding="4">';
     foreach ($items as $item) {
       echo "<tr><td>$item</td></tr>\n";
     }
     echo '</table>';
  }
}
closedir($dir);
?>

所以现在，我需要能够读取和打印每个文件的第3行.我认为它就像在foreach循环中添加数组以回显特定行一样简单?我确实尝试过，但是总的来说，有点混乱:

So now, I need to be able to read and print line 3 of each of the files. I assume that its as simple as adding in array within the foreach loop to echo a specific line? I did try this, but synatctally, it's a bit of a mess:

<?php
$directory = "emails/";
$dir = opendir($directory);
**$lines = file($filename);**
while (($file = readdir($dir)) !== false) {
  $filename = $directory . $file;
  $type = filetype($filename);
  if ($type == 'file') {
     $contents = file_get_contents($filename);
     $items = explode('/n', $contents);
     echo '<table width="500" border="1" cellpadding="4">';
     foreach ($items as $item) {
       **echo "<tr><td>$lines[2]</td></tr>\n";**
     }
     echo '</table>';
  }
}
closedir($dir);
?>

有人可以在这里将我推向正确的方向吗?

Can anyone push me in the right direction here?

推荐答案

使用命令行工具更容易做到这一点:

This is far easier to do with command line tools:

exec("grep '^From: ' *.txt|uniq", $output);

这将仅返回所有文本文件中以From:开头的行.简单的子字符串提取即可为您提供实际的电子邮件地址，并且为您节省了大量PHP的工作.

That'll return ONLY the lines that start with From: from all the text files. A simple substring extraction gets you the actual email address, and you've saved yourself a lot of PHP busywork.

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