问题描述
这是我用于Twitter语义分析的代码:-
This is the Code that I am using for semantic analysis of twitter:-
import pandas as pd
import datetime
import numpy as np
import re
from nltk.tokenize import word_tokenize
from nltk.corpus import stopwords
from nltk.stem.wordnet import WordNetLemmatizer
from nltk.stem.porter import PorterStemmer
df=pd.read_csv('twitDB.csv',header=None,
sep=',',error_bad_lines=False,encoding='utf-8')
hula=df[[0,1,2,3]]
hula=hula.fillna(0)
hula['tweet'] = hula[0].astype(str)
+hula[1].astype(str)+hula[2].astype(str)+hula[3].astype(str)
hula["tweet"]=hula.tweet.str.lower()
ho=hula["tweet"]
ho = ho.replace('\s+', ' ', regex=True)
ho=ho.replace('\.+', '.', regex=True)
special_char_list = [':', ';', '?', '}', ')', '{', '(']
for special_char in special_char_list:
ho=ho.replace(special_char, '')
print(ho)
ho = ho.replace('((www\.[\s]+)|(https?://[^\s]+))','URL',regex=True)
ho =ho.replace(r'#([^\s]+)', r'\1', regex=True)
ho =ho.replace('\'"',regex=True)
lem = WordNetLemmatizer()
stem = PorterStemmer()
fg=stem.stem(a)
eng_stopwords = stopwords.words('english')
ho = ho.to_frame(name=None)
a=ho.to_string(buf=None, columns=None, col_space=None, header=True,
index=True, na_rep='NaN', formatters=None, float_format=None,
sparsify=False, index_names=True, justify=None, line_width=None,
max_rows=None, max_cols=None, show_dimensions=False)
wordList = word_tokenize(fg)
wordList = [word for word in wordList if word not in eng_stopwords]
print (wordList)
输入即a:-
tweet
0 1495596971.6034188::automotive auto ebc greens...
1 1495596972.330948::new free stock photo of cit...
以以下格式获取输出(wordList):-
getting output ( wordList) in this format:-
tweet
0
1495596971.6034188
:
:automotive
auto
我只希望以行格式输出一行.我该怎么做?如果您有更好的Twitter语义分析代码,请与我分享.
I want the output of a row in a row format only. How can I do it?If you have a better code for semantic analysis of twitter please share it with me.
推荐答案
简而言之:
df['Text'].apply(word_tokenize)
或者如果您想添加另一列来存储标记化的字符串列表:
Or if you want to add another column to store the tokenized list of strings:
df['tokenized_text'] = df['Text'].apply(word_tokenize)
有专门为Twitter文本编写的令牌生成器,请参见 http://www.nltk.org/api/nltk.tokenize.html#module-nltk.tokenize.casual
There are tokenizers written specifically for twitter text, see http://www.nltk.org/api/nltk.tokenize.html#module-nltk.tokenize.casual
要使用nltk.tokenize.TweetTokenizer
:
from nltk.tokenize import TweetTokenizer
tt = TweetTokenizer()
df['Text'].apply(tt.tokenize)
类似于:
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