Ruby：在字符串中转义特殊字符

问题描述

我正在PHP中编写一个与 mysqli_real_escape_string 相同的方法。它需要一个字符串，并转义任何危险字符。我已经找到了一种可以为我做的方法，但是找不到它。所以我试图自己写一个。

I am trying to write a method that is the same as mysqli_real_escape_string in PHP. It takes a string and escapes any 'dangerous' characters. I have looked for a method that will do this for me but I cannot find one. So I am trying to write one on my own.

这是我迄今为止（我在，它的工作原理）：

This is what I have so far (I tested the pattern at Rubular.com and it worked):

# Finds the following characters and escapes them by preceding them with a backslash. Characters: ' " . * / \ -
def escape_characters_in_string(string)
  pattern = %r{ (\'|\"|\.|\*|\/|\-|\\) }
  string.gsub(pattern, '\\\0') # <-- Trying to take the currently found match and add a \ before it I have no idea how to do that).
end

我正在使用 start_string 作为我想要更改的字符串，而 correct_string 正如我想要的那样 start_string 变成：

And I am using start_string as the string I want to change, and correct_string as what I want start_string to turn into:

start_string = %("My" 'name' *is* -john- .doe. /ok?/ C:\\Drive)
correct_string = %(\"My\" \'name\' \*is\* \-john\- \.doe\. \/ok?\/ C:\\\\Drive)

有人可以帮助我确定为什么我没有得到我想要的输出（ correct_string ）或告诉我在哪里可以找到一个这样做的方法，甚至更好地告诉我两者？非常感谢！

Can somebody try and help me determine why I am not getting my desired output (correct_string) or tell me where I can find a method that does this, or even better tell me both? Thanks a lot!

推荐答案

您的示例中没有正确定义您的模式。

Your pattern isn't defined correctly in your example. This is as close as I can get to your desired output.

输出

"\\\"My\\\" \\'name\\' \\*is\\* \\-john\\- \\.doe\\. \\/ok?\\/ C:\\\\Drive"

将要采取一些调整，以获得100％，但至少可以看到您现在的行为模式。

It's going to take some tweaking on your part to get it 100% but at least you can see your pattern in action now.

  def self.escape_characters_in_string(string)
    pattern = /(\'|\"|\.|\*|\/|\-|\\)/
    string.gsub(pattern){|match|"\\"  + match} # <-- Trying to take the currently found match and add a \ before it I have no idea how to do that).
  end

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