使用布尔值的switch / case请求

问题描述

我正在尝试创建一个方法来检查Login（用户名和密码）是否至少包含6个字符。

I'm trying to create a method which checks if the Login (username and password) has a minimum of 6 charakters.

要意识到我创建了这个方法 public void checkLoginData（final String username，final String password）。在那个方法中，我创建了booleans（用户和pass），我可以创建4个不同的布尔链：

To realize that I created this method public void checkLoginData(final String username, final String password). In that method, I create to booleans (user and pass), with those I can create 4 different boolean-chains:

• user：true pass：true


• user：false pass：true


• user：false pass：false


• user： true pass：false

• user: true pass: true
• user: false pass: true
• user: false pass: false
• user: true pass: false

现在我想为每个人做一个切换/案例请求，但我没有得到如何实现...

Now I'd like to do a switch/case request for each of them, but I don't get how to realize that...

如果你问我为什么需要这个开关，我只是觉得我需要它，因为我想为这些4布尔链，它表示/显示不同的东西。另外，我想用性感的java方式做这件事，而不是成千上万的不同'ifs'：P，请帮助！

If you ask why I need the switch, I just think I need it, because I'd like to do for every of those 4 boolean-chains, that it does/show something diffrent. Also I'd like to do this in a sexy-java-way not with tousands of diffrent 'ifs' :P, Please help!

这是方法的代码：

public void checkLoginData(final String username, final String password){

    boolean user, pass;

    if (username.length() < 6){
        user = false;
    }else {
        user = true;
    }

    if (password.length() < 6){
        pass = false;
    }else {
        pass = true;
    }

    boolean[] logindaten = {user, pass};



}

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提前帮助的Thx！

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Thx for the help in Advance!

最好的问候safari

Best Regards safari

推荐答案

你不能只在整数类型上切换 boolean [] 。要将布尔值转换为int，您可以使用2位布尔值的位掩码，例如：

You can't switch over boolean[], only over integral types. To convert the booleans to an int, you could use a bit mask for the 2 booleans, like for example this:

int val = 0;
if (user) val |= 0x1;
if (pass) val |= 0x2;

switch (val) {
case 0: // Both too short
case 1: // User Ok, pass too short
case 2: // User too short, pass ok
case 3: // Both Ok
}

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