如何获取PHP DI容器?

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问题描述

如何使用 PHP DI 加载数据库容器?这是我到目前为止尝试的变体之一.

How do I load a database container using PHP DI?This is one of the variations I have tried up until now.

Settings.php

<?php
use MyApp\Core\Database;
use MyApp\Models\SystemUser;

return [
    'Database'      => new Database(),
    'SystemUser'    => new SystemUser()
];

init.php

$containerBuilder   = new \DI\ContainerBuilder();
$containerBuilder->addDefinitions('Settings.php');
$container          = $containerBuilder->build();

SystemUserDetails.php

<?php
namespace MyApp\Models\SystemUser;

use MyApp\Core\Database;
use MyApp\Core\Config;
use MyApp\Helpers\Session;


/**
 *
 *  System User Details Class
 *
 */
class SystemUserDetails
{

/*=================================
=            Variables            =
=================================*/

    private $db;


/*===============================
=            Methods            =
================================*/

    /**
     *
     *  Construct
     *
     */
    public function __construct(Database $db)
    {
        # Get database instance
        // $this->db           = Database::getInstance();
        $this->db           = $db;
    }


    /**

数据库不会自动加载吗?

Shouldn't the database get loaded automatically?

踪迹:

目前，我的主index.php文件扩展了init.php，这是它创建容器的文件(文章中粘贴的代码部分).

Currrently, My main index.php file extends init.php which is the file where it create the container (pasted code part in the post).

然后我调用App类，该类将获取URL(mysite.com/login/user_login)并实例化一个新的控制器类并运行所提到的方法，在这种情况下，它是第一页-MyApp/Contollers/Login.php.

Then I call the App class, which fetches the URL(mysite.com/login/user_login) and instantiate a new controller class and run the mentioned method, in this case, it's the first page - MyApp/Contollers/Login.php.

user_login方法获取凭据，对其进行验证，如果它们有效，则使用SystemUser对象进行登录.

The user_login method fetches the credentials, validate them, and if they are valid, uses the SystemUser object to login.

SystemUser类:

SystemUser class:

namespace MyApp\Models;


class SystemUser
{

    public $id;

    # @obj SystemUser profile information (fullname, email, last_login, profile picture, etc')
    protected $systemUserDetatils;


    public function __construct($systemUserId = NULL)
    {
        # Create systemUserDedatils obj
        $this->systemUserDetatils   = new \MyApp\Models\SystemUser\SystemUserDetails();

        # If system_user passed
        if ( $systemUserId ) {

            # Set system user ID
            $this->id                   = $systemUserId;

            # Get SysUser data
            $this->systemUserDetatils->get($this);

        } else {

            # Check for sysUser id in the session:
            $systemUserId                   = $this->systemUserDetatils->getUserFromSession();

            # Get user data from session
            if ( $systemUserId ) {

                # Set system user ID
                $this->id                   = $systemUserId;

                # Get SysUser data
                $this->systemUserDetatils->get($this);
            }
        }
    }
}

推荐答案

PHP-DI正常工作.

PHP-DI is working correctly.

在您的SystemUser课堂上，您正在做

In your SystemUser class you are doing:

$this->systemUserDetatils   = new \MyApp\Models\SystemUser\SystemUserDetails();

SystemUserDetails的构造函数需要一个您未传递的Database对象.

The constructor for SystemUserDetails requires a Database object, which you are not passing.

通过直接调用new，您没有使用PHP-DI .通过这样做，您可以隐藏依赖关系，而这正是您想使用依赖关系注入系统时要避免的东西.

By calling new directly, you are not using PHP-DI. By doing this you are hiding the dependency, which is exactly what you are supposedly trying to avoid if you want to use a dependency injection system.

如果SystemUser 依赖(需要")SystemUserDetails，则该依赖应该是显式的(例如，在其构造函数中声明).

If SystemUser depends ("needs") SystemUserDetails, the dependency should be explicit (e.g. declared in its constructor).

此外:对于这样的系统，您不需要定义文件.而且您在问题中显示的定义文件没有遵循 PHP-DI .

Furthermore: You do not need a definitions file for a system like this. And the definitions file you show in your question doesn't follow the best practices recommended by PHP-DI.

您的设计远非完美，我不确定您的最终目标，但是如果您这样做，它可能会起作用:

Your design is far from perfect, and I'm not sure of your end-goals, but if you did something like this, it could work:

<?php
// src/Database.php

class Database {
    public function getDb() : string {
        return 'veryDb';
    }
}

<?php
// src/SystemUserDetails.php

class SystemUserDetails {

    protected $db;

    public function __construct(Database $db)
    {
        $this->db           = $db;
    }

    public function getDetails() {
       return "Got details using " . $this->db->getDb() . '.';
    }
}

<?php
// src/SystemUser.php
class SystemUser {

    protected $details;

    public function __construct(SystemUserDetails $details, $userId=null) {

        $this->details = $details;
    }

    public function getUser() {
       return "Found User. " .$this->details->getDetails();
    }
}

<?php
//init.php
require_once('vendor/autoload.php');

// build the container. notice I do not use a definition file.
$containerBuilder   = new \DI\ContainerBuilder();
$container          = $containerBuilder->build();

// get SystemUser instance from the container.
$userInstance = $container->get('SystemUser');

echo $userInstance->getUser(), "\n";

这将导致:

Found User. Got details using veryDb.

这篇关于如何获取PHP DI容器?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！