使用Mongo按组计算多个不同的字段

问题描述

我有一个数据集，外观为

I have a data set looks as

{"BrandId":"a","SessionId":100,"UserName":"tom"}
{"BrandId":"a","SessionId":200,"UserName":"tom"}
{"BrandId":"b","SessionId":300,"UserName":"mike"}

我想按Brandid计算不同的会话和用户名组，示例sql如下:

I would like to count distinct session and username group by brandid, the sample sql is like:

select brandid,count_distinct(sessionid),count_distinct(username)
from data
group by brandid

我试图编写Mongo DB，我当前的代码如下，并且不起作用.反正有什么办法使它起作用?

I tried to write Mongo DB, my current code is as following and it does not work. Is there anyway to make it work?

db.logs.aggregate([
    {$group:{
        _id:{brand:"$BrandId",user:"$UserName",session:"$SessionId"},
        count:{$sum:1}}},
    {$group:{
        _id:"$_id.brand",
        users:{$sum:"$_id.user"},
        sessions:{$sum:"$_id.session"}
    }}
])

对于特定示例，预期计数为

for the certain example, the expected count is

{"BrandId:"a","countSession":2,"countUser":1}
{"BrandId:"b","countSession":1,"countUser":1}

如果您了解SQL，则预期结果与我提到的SQL相同.

if you know SQL, the expect result is as same as the SQL I mentioned.

推荐答案

您可以使用 $addToSet ，以在$group期间累积不同的SessionId和UserName值集，然后添加 $project 阶段到使用 $size 运算符以获取每个集合的大小:

You can do this by using $addToSet to accumulate the distinct set of SessionId and UserName values during the $group, and then adding a $project stage to your pipeline that uses the $size operator to get the size of each set:

db.logs.aggregate([
    {$group: {
        _id: '$BrandId',
        sessionIds: {$addToSet: '$SessionId'},
        userNames: {$addToSet: '$UserName'}
    }},
    {$project: {
        _id: 0,
        BrandId: '$_id',
        countSession: {$size: '$sessionIds'},
        countUser: {$size: '$userNames'}
    }}
])

结果:

{
    "BrandId" : "b",
    "countSession" : 1,
    "countUser" : 1
},
{
    "BrandId" : "a",
    "countSession" : 2,
    "countUser" : 1
}

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