如何将输入存储在数组中，并在输入（-1）时停止并存储？

问题描述

我正在尝试制作一个程序，首先提示用户菜单的菜单选项从0到7开始。



我有一个switch语句来检查输入的数字。这个程序还没有完成我开始在构建列表选项中，我是用户输入值以将其存储到数组中，当用户输入-1时我希望它将-1存储在数组并显示一条说循环结束的printf消息。



我做了个案陈述，只显示用户输入的菜单选项。



更新：

I am trying to make a program that first prompts the user with a menu with menu options starting from 0 to 7.

I have a switch statement to check for what numbers are entered. This program is not finished I am starting on the "build list option" where I was the user to enter value to have it stored into an array, when the user enters a "-1" I want it to store the -1 in the array and display a printf message saying "loop ended".

I made case statements to just display the menu option the user entered, for now.

UPDATE:

The problem is the program does not keep prompting the user for ("Enter a value for the array (-1 to quit: \n") and does not quit and store -1 in the array when finished.

When I enter a '0' for my build menu option it prompts me for a value...when I enter a number such as a '1' it will display the menu option..instead of looping the "enter a value" statement until a -1 one is entered..

任何提示和建议都会很棒

Any tips and suggestions would be great

#include <stdio.h>
#include <stdlib.h>
#define SIZE 50

void main ()
{
	int i = 0;
	int userinput[SIZE];
	int x = 0;
	do
	{
		printf("===DSCI0====\n");
		printf("0. Build List\n");
		printf("1. Display List Forward\n");
		printf("2. Display List Backwards\n");
		printf("3. Insert into list\n");
		printf("4. Append into list\n");
		printf("5. Obtain from List\n");
		printf("6. Clear List\n");
		printf("7. Quit\n");
		printf("What is your menu option?\n");
		scanf("%d", &i);

	} while(i < 0 || i > 7);

	switch(i)
	{
		case(0) :
			for (x = 0; x < SIZE; x++);
			{
				printf("Enter a value for the array (-1 to quit): \n");
				scanf("%x", &userinput[x]);
				if(userinput[x] == -1)
				{
					printf("loop ended\n");
					break;
				}
			}
	case(1) : printf("Display List Fwd\n");
			break;
	case(2) : printf("Display List Bkwd\n");
			break;
	case(3) : printf("Insert into list\n");
			break;
	case(4) : printf("Append into list\n");

		break;
	case(5) : printf("Obtain from list\n");
			break;
	case(6) : printf("Clear List\n");
			break;
	case(7) : printf("Good-Bye\n");
		  exit(0);
		  break;
	default : printf("Enter a value 0-7\n");
			exit(0);
			break;
	}

}

我尝试过：



我尝试改变switch语句，乱用for循环和if语句。

What I have tried:

I tried changing the switch statement around, messed around with the for loops and if statements.

推荐答案

scanf("%d", &i);

但你打开 x

but you switch on x

switch(x)

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