如何命名文件?

问题描述

对于循环中的每个迭代，我都需要提供迭代次数"作为文件名，例如，目标是保存:

For every iteration in my loop for, I need to give 'the number of my iteration' as a name for the file, for example, the goal is to save:

my first iteration in the first file.
my second iteration in the second file.
....

我为此使用了numpy库，但是我的代码没有给我所需的解决方案，实际上，我的实际代码使我必须在每次迭代后输入文件名，如果我有6个，这很容易或7次迭代，但是在我有100次迭代的情况下，这没有意义:

I use for that the library numpy, but my code doesn't give me the solution that i need, in fact my actual code oblige me to enter the name of the file after each iteration, that is easy if I have 6 or 7 iteration, but i am in the case that I have 100 iteration, it doesn't make sense:

for line, a in enumerate(Plaintxt_file):
    #instruction
    #result
    fileName = raw_input()
    if(fileName!='end'):
        fileName = r'C:\\Users\\My_resul\\Win_My_Scripts\\'+fileName
        np.save(fileName+'.npy',Result)
ser.close()

如果您能帮助我，我将不胜感激.

I would be very grateful if you could help me.

推荐答案

从行号创建文件名:

for line, a in enumerate(Plaintxt_file):
    fileName = r'C:\Users\My_resul\Win_My_Scripts\file_{}.npy'.format(line)
    np.save(fileName, Result)

此操作以文件名file_0.npy开头.如果要以1开头，请在enumerate中指定起始索引:

This start with file name file_0.npy.If you like to start with 1, specify the starting index in enumerate:

for line, a in enumerate(Plaintxt_file, 1):

当然，这是假设您在其他任何地方都不需要line以0开头.

Of course, this assumes you don't need line starting with 0 anywhere else.

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