如何检查 Java 7 路径的扩展名

问题描述

我想检查是否有 路径(在 Java 7 中引入)以某个扩展结束.我像这样尝试了 endsWith() 方法:

Path path = Paths.get("foo/bar.java")if (path.endsWith(".java")){//做东西}

然而，这似乎不起作用，因为 path.endsWith(".java") 返回 false.似乎 endsWith() 方法仅在最终目录分隔符(例如 bar.java)之后的所有内容都完全匹配时才返回 true，这对于我.

那么如何查看路径的文件扩展名?

解决方案

Java NIO 的 PathMatcher 提供 FileSystem.getPathMatcher(String syntaxAndPattern):

PathMatcher matcher = FileSystems.getDefault().getPathMatcher("glob:*.java");路径文件名 = ...;如果(匹配器.匹配(文件名)){System.out.println(文件名);}

有关详细信息，请参阅查找文件教程.>

I'd like to check if a Path (introduced in Java 7) ends with a certain extension. I tried the endsWith() method like so:

Path path = Paths.get("foo/bar.java")
if (path.endsWith(".java")){
    //Do stuff
}

However, this doesn't seem to work because path.endsWith(".java") returns false. It seems the endsWith() method only returns true if there is a complete match for everything after the final directory separator (e.g. bar.java), which isn't practical for me.

So how can I check the file extension of a Path?

解决方案

Java NIO's PathMatcher provides FileSystem.getPathMatcher(String syntaxAndPattern):

PathMatcher matcher = FileSystems.getDefault().getPathMatcher("glob:*.java");

Path filename = ...;
if (matcher.matches(filename)) {
    System.out.println(filename);
}

See the Finding Files tutorial for details.

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