根据C#中整数元组列表的item2进行不同的应用

问题描述

我有一个整数元组列表

List<Tuple<int, int>> list =  new  List<Tuple<int, int>>();
list.Add(new Tuple<int, int>(1,12));
list.Add(new Tuple<int, int>(1,2));
list.Add(new Tuple<int, int>(1,18));
list.Add(new Tuple<int, int>(1,12));

在这种情况下，我想删除item2的冗余值

I want to remove the redundant value of item2 which is 12 in this case

更新后的列表也应该是列表". (相同的类型)，但具有不同的值.类型为List>的新元组应仅包含以下内容:

The updated list should also be List>. (same type) but with distinct values.The new tuple of type List> should contain only following:

 list.Add(new Tuple<int, int>(1,2));
 list.Add(new Tuple<int, int>(1,18));
 list.Add(new Tuple<int, int>(1,12));

有帮助吗?

推荐答案

如果只需要唯一的数字对，则可以使用Distinct()轻松完成:

If you want only the unique pairs of numbers this can easily be done by using Distinct():

list = list.Distinct().ToList();

如果仅考虑删除 only Item2的重复项，则使用GroupBy()和Select()每个组的First():

If you only care about removing duplicates of only Item2, then use GroupBy() and Select() the First() of each group:

list = list.GroupBy(x => x.Item2).Select(x => x.First());

我做了一个小提琴此处演示了这两种方法

I made a fiddle here that demonstrates both methods

编辑

从您的最新评论中，您似乎想使用我建议的第二种方法(GroupBy Item2，然后选择每个组的第一个).

From your latest comment, it sounds like you want to use the second method I have proposed (GroupBy Item2 and Select the First of each Group).

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