本文介绍了值不会更新到asp.net中的mysql数据库的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
MySqlConnection con = new MySqlConnection();
MySqlCommand com = new MySqlCommand();
MySqlDataReader dr;
con = new MySqlConnection(ConfigurationManager.ConnectionStrings["netConnectionString"].ToString());
con.Open();
com = new MySqlCommand("select full_name,email,age,user_name,country,password,education,about,interest from users where user_name='" + Session["user"] + "'", con);
dr = com.ExecuteReader();
if (dr.Read())
{
TextBox5.Text = dr[0].ToString();
TextBox4.Text = dr[1].ToString();
TextBox6.Text = dr[2].ToString();
TextBox7.Text = dr[3].ToString();
TextBox8.Text = dr[4].ToString();
TextBox9.Text = dr[5].ToString();
TextBox1.Text = dr[6].ToString();
TextBox2.Text = dr[7].ToString();
TextBox3.Text = dr[8].ToString();
}
}
protected void Button2_Click(object sender, EventArgs e)
{
MySqlConnection con = new MySqlConnection();
string str = ConfigurationManager.ConnectionStrings["netConnectionString"].ConnectionString;
con.ConnectionString = str;
con.Open();
if (con.State.ToString() == "Open")
{
MySqlCommand cmd = new MySqlCommand("UPDATE users SET email=@b,age=@c,user_name=@d,country=@e,password=@f, education=@g,about=@h,interest=@i WHERE user_name=@userName", con);
cmd.Parameters.AddWithValue("@b", TextBox4.Text);
cmd.Parameters.AddWithValue("@c", TextBox6.Text);
cmd.Parameters.AddWithValue("@d", TextBox7.Text);
cmd.Parameters.AddWithValue("@e", TextBox8.Text);
cmd.Parameters.AddWithValue("@f", TextBox9.Text);
cmd.Parameters.AddWithValue("@g", TextBox1.Text);
cmd.Parameters.AddWithValue("@h", TextBox2.Text);
cmd.Parameters.AddWithValue("@i", TextBox3.Text);
cmd.Parameters.AddWithValue("@userName", Session["user"].ToString());
cmd.ExecuteNonQuery();
TextBox1.Visible = false;
TextBox2.Visible = false;
TextBox3.Visible = false;
Label5.Text = "Well done profile updated!!";
con.Close();
此代码显示值但不将新值更新到数据库中帮助我使用此编码!!
this code is showing the values but not updating the new values into database help me with this coding!!
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