问题描述
如何使用休眠注释来验证枚举成员字段?以下方法不起作用:
How can I use hibernate annotations to validate an enum member field?The following does not work:
enum UserRole {
USER, ADMIN;
}
class User {
@NotBlank //HV000030: No validator could be found for type: UserRole.
UserRole userRole;
}
推荐答案
请注意,您还可以创建验证器来检查字符串是否属于枚举.
Note you can also create a validator to check a String is part of an enumeration.
public enum UserType { PERSON, COMPANY }
@NotNull
@StringEnumeration(enumClass = UserCivility.class)
private String title;
@Documented
@Constraint(validatedBy = StringEnumerationValidator.class)
@Target({ METHOD, FIELD, ANNOTATION_TYPE, PARAMETER, CONSTRUCTOR })
@Retention(RUNTIME)
public @interface StringEnumeration {
String message() default "{com.xxx.bean.validation.constraints.StringEnumeration.message}";
Class<?>[] groups() default {};
Class<? extends Payload>[] payload() default {};
Class<? extends Enum<?>> enumClass();
}
public class StringEnumerationValidator implements ConstraintValidator<StringEnumeration, String> {
private Set<String> AVAILABLE_ENUM_NAMES;
@Override
public void initialize(StringEnumeration stringEnumeration) {
Class<? extends Enum<?>> enumSelected = stringEnumeration.enumClass();
//Set<? extends Enum<?>> enumInstances = EnumSet.allOf(enumSelected);
Set<? extends Enum<?>> enumInstances = Sets.newHashSet(enumSelected.getEnumConstants());
AVAILABLE_ENUM_NAMES = FluentIterable
.from(enumInstances)
.transform(PrimitiveGuavaFunctions.ENUM_TO_NAME)
.toSet();
}
@Override
public boolean isValid(String value, ConstraintValidatorContext context) {
if ( value == null ) {
return true;
} else {
return AVAILABLE_ENUM_NAMES.contains(value);
}
}
}
这很好,因为您不会丢失错误值"的信息.您可以收到类似
This is nice because you don't loose the information of the "wrong value". You can get a message like
值someBadUserType"不是有效的用户类型.有效用户类型值为:个人、公司
编辑
对于那些想要非 Guava 版本的人来说,它应该适用于以下内容:
For those who want a non-Guava version it should work with something like:
public class StringEnumerationValidator implements ConstraintValidator<StringEnumeration, String> {
private Set<String> AVAILABLE_ENUM_NAMES;
public static Set<String> getNamesSet(Class<? extends Enum<?>> e) {
Enum<?>[] enums = e.getEnumConstants();
String[] names = new String[enums.length];
for (int i = 0; i < enums.length; i++) {
names[i] = enums[i].name();
}
Set<String> mySet = new HashSet<String>(Arrays.asList(names));
return mySet;
}
@Override
public void initialize(StringEnumeration stringEnumeration) {
Class<? extends Enum<?>> enumSelected = stringEnumeration.enumClass();
AVAILABLE_ENUM_NAMES = getNamesSet(enumSelected);
}
@Override
public boolean isValid(String value, ConstraintValidatorContext context) {
if ( value == null ) {
return true;
} else {
return AVAILABLE_ENUM_NAMES.contains(value);
}
}
}
要自定义错误消息并显示适当的值,请检查:https://stackoverflow.com/a/19833921/82609
And to customize the error message and display the appropriate values, check this: https://stackoverflow.com/a/19833921/82609
这篇关于如何在枚举中使用 Hibernate 验证注释?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!