问题描述
我有以下问题：
第一：我试图做一个32位按位上留下的大量转移，以及由于某种原因总是返回的数字原样。例如：
First: I am trying to do a 32-spaces bitwise left shift on a large number, and for some reason the number is always returned as-is. For example:
echo(516103988<<32); // echoes 516103988
由于比特左移一个空格是乘以2的等效，我试图由2 ^ 32数相乘，和它的工作原理，它返回2216649749795176448
Because shifting the bits to the left one space is the equivalent of multiplying by 2, i tried multiplying the number by 2^32, and it works, it returns 2216649749795176448.
二：我必须从上述点增加9379到号：
Second: I have to add 9379 to the number from the above point:
printf('%0.0f', 2216649749795176448 + 9379); // prints 2216649749795185920
应该打印：2216649749795185827
Should print: 2216649749795185827
推荐答案
根据帕斯卡·马丁的建议，我想无论是BCMath和GMP延伸，并与以下解决方案提出了：
Based on Pascal MARTIN's suggestions, i tried both the BCMath and the GMP extension and came up with the following solutions:
使用BCMath：
$a = 516103988;
$s = bcpow(2, 32);
$a = bcadd(bcmul($a, $s), 9379);
echo $a; // works, echoes 2216649749795185827
通过GMP：
$a = gmp_init(516103988);
$s = gmp_pow(gmp_init(2), 32);
$a = gmp_add(gmp_mul($a, $s), gmp_init(9379));
echo gmp_strval($a); // also works
据我了解，有一个在服务器GMP再上安装BCMath大得多的机会，所以我将使用第一个解决方案。
From what i understand, there is a far greater chance for BCMath to be installed on the server then GMP, so i will be using the first solution.
感谢：）
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