有问题的C程序找到2个数字之间的公因数。

本文介绍了有问题的C程序找到2个数字之间的公因数。的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 程序不会打印常用的，而是打印初始化值，该值旨在按程序中的编码递增。 我认为问题在于while循环。 如果更正以下代码而不是编写完全不同的代码，将不胜感激。 我尝试了什么： ＃ include < conio.h > #include < stdio.h > int main（）{ int a，b，i，j; int total_a = 0 ，total_b = 0 ; printf（ 输入你的整数：\ n）; scanf（ ％d％d，& a，& b）; for （i = 1 ，j = 1 ; i< = a，j< = b; i ++，j ++）{ if （a ％i == 0 ） total_a = total_a * 10 + i; if （b％j == 0 ） total_b = total_b * 10 + j; } / * printf（％d％d ，total_a，total_b）; int total = 0; printf（％d，total）; * / int rem_a，rem_b，total = 0 ; while （total_a！= 0 ）{ rem_a = total_a％10; while （total_b！= 0 ）{ rem_b = total_b％10; if （rem_a == rem_b）{ total = total * 10 + rem_a; } total_b / = 10 ; } total_a / = 10 ; } printf（ ％d，总计） ; return 0 ; } 解决方案 嗯。你需要考虑更多：你的代码没有你想象的那样。 for（i = 1，j = 1; i< = a， j< = b; i ++，j ++）{ 在这个循环中， i 和 j 将始终具有相同的值;他们将从一开始，然后他们都将是两个，依此类推。我不确定他们什么时候会停止，因为我之前没有看过带逗号的情况，我怀疑它会编译 - 我在平板电脑上并且目前没有C编译器我不能检查，但我不认为它是有效的C代码。 可能，你需要一对嵌套的循环，而不是一个循环...... The program doesn't print the common but instead the initialized value which is intended to increment as coded in the program.And i think the problem lies in the while loop.it would be appreciated if the following code is corrected instead of writing totally different code.What I have tried:#include <conio.h>#include <stdio.h>int main(){int a, b, i, j;int total_a=0, total_b=0;printf("Enter your integers: \n");scanf(" %d%d", &a, &b);for(i=1, j=1; i<=a,j<=b; i++,j++){if(a%i==0)total_a = total_a*10 + i;if(b%j==0)total_b = total_b*10 + j;}/*printf(" %d %d", total_a, total_b);int total=0;printf(" %d", total);*/int rem_a, rem_b, total =0;while(total_a!=0){rem_a = total_a%10;while(total_b!=0){rem_b =total_b%10;if(rem_a==rem_b){total = total*10 + rem_a;}total_b/=10;}total_a/=10;}printf(" %d", total);return 0;} 解决方案 Um. You need to think some more about this: your code doesn't do what you think it will.for(i=1, j=1; i<=a,j<=b; i++,j++){Inside this loop, i and j will always have the same value; they will both start at one, then they will both be two, and so on. I'm not sure when they will stop, because I've not seen a condition with a comma in it before and I doubt it will compile - I'm on a tablet and have no C compiler at the moment s I can't check, but I don't think it's valid C code.Probably, you need a nested pair of loops, rather than a single loop... 这篇关于有问题的C程序找到2个数字之间的公因数。的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！