为什么我不能从一个Ajax函数返回的responseText

为什么我不能从一个Ajax函数返回的responseText

本文介绍了为什么我不能从一个Ajax函数返回的responseText?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

下面是我的Ajax功能的一部分。出于某种原因,我想不通,我可以的警报()的的responseText,但不能的返回的的responseText。任何人都可以帮忙吗?我需要在另一功能中使用该值。

  http.onreadystatechange =功能(){
    如果(http.readyState == 4和&安培; http.status == 200){
        返回http.responseText;
    }
}
 

解决方案

您将无法处理,你是从你的异步回调返回的返回值。您应该直接处理的responseText 中的回调,或致电一个辅助函数来处理响应:

  http.onreadystatechange =功能(){
    如果(http.readyState == 4和&安培; http.status == 200){
        用handleResponse(http.responseText);
    }
}

功能用handleResponse(响应){
    警报(响应);
}
 

Here is part of my Ajax function. For some reason that I cannot figure out, I am able to alert() responseText but not able to return responseText. Can anybody help? I need that value to be used in another function.

http.onreadystatechange = function(){
    if( http.readyState == 4 && http.status == 200 ){
        return http.responseText;
    }
}
解决方案

You will not be able to handle the return value that you are returning from your asynchronous callback. You should handle the responseText within the callback directly, or call a helper function to handle the response:

http.onreadystatechange = function () {
    if (http.readyState == 4 && http.status == 200) {
        handleResponse(http.responseText);
    }
}

function handleResponse (response) {
    alert(response);
}

这篇关于为什么我不能从一个Ajax函数返回的responseText?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-24 09:42