问题描述
我必须在文件中找到字符串：
I must find in a file this string:
200 https://www.example.example
价值200 randomic，我一定要找到每一个HTTP返回code（200前，301，404等...等）
The value 200 is randomic, I must find every HTTP return code (ex 200, 301, 404 etc...etc)
我怎么可以grep仅此字符串返回code变量中（我不想指定grep命令每返回code）？
How can I grep only this string with return code variable (I don't want specify every return code in grep command)?
cat file.txt | grep "*** http*"
不过，这是行不通的。
But it doesn't work.
推荐答案
所以你要匹配开头的三位数任何线路，其次是HTTP？
So you want to match any line starting with a three digit number, followed by "http"?
grep -E '^[0-9]{3} http' file.txt
更精确由fedorqui（感谢）的建议是这样的：
More accurate as suggested by fedorqui (thanks) would be this:
grep -E '^[1-5][0-9]{2} http' file.txt
这在范围100-599，这是接近HTTP状态codeS的范围相匹配的号码。
This matches numbers in the range 100-599, which is closer to the range of HTTP status codes.
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