加倍除以浮点值

问题描述

我有我相信这将一个int转换成浮点值拆分成价值的符号指数和部分组件的功能。利用IEEE 754重新present浮点值。

 符号试验（无符号X）{
    //拆分符号指数和部分的给定的位，结合以返回    无符号整数符号=（X安培;为0x80000000）GT;＆GT; 31;
    unsigned int类型博览会=（X安培; 0x7F800000）GT;＆GT; 23;
    unsigned int类型压裂=（X安培; 0x007fffff）;    返回（符号＆LT;＆LT; 31）| （世博＆LT;＆LT; 23）|压裂;
}
 

我不确定但我怎么可能从这个浮点重新presentation计算一半或一倍值。

 符号一倍（无符号X）{
    //获取浮动
    //浮= unsigned int类型浮动
    // doubleFloat = 2 *˚F
    //如果浮动不是一个数字
        //返回无符号的浮动
    //否则返回半浮球无符号整数    无符号整数符号=（X安培;为0x80000000）GT;＆GT; 31;
    unsigned int类型博览会=（X安培; 0x7F800000）GT;＆GT; 23;
    unsigned int类型压裂=（X安培; 0x007fffff）;    如果（世博==为0xFF）
        返回UF;
    否则...
}
 

解决方案

看来你使用的是IEEE 754重新present浮点值。

如果您要仔细二进制重新presentation，你只需要通过1 expoent递增。如果你想要半也是如此，只是减1

请记住，这是真的只有当您的号码是在正常范围内，甚至包括加倍或减半后

I have the function which I believe will convert an int into a floating point value split into the sign exponent and fraction components of the value. Using IEEE 754 to represent Float values.

unsigned test(unsigned x) {
    // split the given bits of sign exponent and fraction, combine to return

    unsigned int sign = (x & 0x80000000) >> 31;
    unsigned int expo = (x & 0x7F800000) >> 23;
    unsigned int frac = (x & 0x007fffff);

    return (sign << 31) | (expo << 23) | frac;
}

I'm unsure however how I could compute the halved or doubled values from this floating point representation.

unsigned doubled(unsigned x) {
    // get float
    // float = unsigned int to float
    // doubleFloat  = 2*f
    // if float is not a number
        // return unsigned float
    // else return unsigned integer of half float

    unsigned int sign = (x & 0x80000000) >> 31;
    unsigned int expo = (x & 0x7F800000) >> 23;
    unsigned int frac = (x & 0x007fffff);

    if (expo == 0xff)
        return uf;
    else ...
}

解决方案

It seems that you are using IEEE 754 to represent Float values.

If you want to double the binary representation, you just need to increment by 1 the expoent. The same is true if you want to half, just decrement by 1

Remember that this is true only if your number is in normal range, including even after doubling or halving

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