问题描述
我想将我作为字符串获得的一些数字转换为双精度数，但这些数字不在美国标准语言环境中，而是在不同的语言环境中.我该怎么做?
I want to convert some numbers which I got as strings into Doubles, but these numbers are not in US standard locale, but in a different one. How can I do that?
推荐答案
试试 java.text.NumberFormat.来自 Javadocs:
Try java.text.NumberFormat. From the Javadocs:
要为不同的区域设置格式化数字，请在调用 getInstance 时指定它.
NumberFormat nf = NumberFormat.getInstance(Locale.FRENCH);
您还可以使用 NumberFormat 来解析数字:
You can also use a NumberFormat to parse numbers:
myNumber = nf.parse(myString);
parse() 返回一个 编号;所以要获得一个double，你必须调用myNumber.doubleValue():
parse() returns a Number; so to get a double, you must call myNumber.doubleValue():
double myNumber = nf.parse(myString).doubleValue();
请注意，parse() 永远不会返回 null，因此这不会导致 NullPointerException.相反，如果失败，parse 会抛出一个检查过的 ParseException.
Note that parse() will never return null, so this cannot cause a NullPointerException. Instead, parse throws a checked ParseException if it fails.
我最初说还有另一种方法可以转换为double:将结果转换为Double并使用拆箱.我认为由于使用了 NumberFormat 的通用实例(根据 getInstance)，它总是返回一个 Double.但是 DJClayworth 指出 parse(String, ParsePosition)(由 parse(String) 调用)表示如果可能返回一个 Long.因此，将结果转换为 Double 是不安全的，不应尝试！
谢谢，DJClayworth！
I originally said that there was another way to convert to double: cast the result to Double and use unboxing. I thought that since a general-purpose instance of NumberFormat was being used (per the Javadocs for getInstance), it would always return a Double. But DJClayworth points out that the Javadocs for parse(String, ParsePosition) (which is called by parse(String)) say that a Long is returned if possible. Therefore, casting the result to Double is unsafe and should not be tried!
Thanks, DJClayworth!
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