尝试资源：必须抛出或捕获close（）方法的异常？

问题描述

如果错误，请更正我：在Java 7的try-with-resources语句中，资源的 close（）方法抛出的任何异常都必须声明为抛出通过我的方法，或者我必须将另一个 try 中的整个尝试包装起来，它捕获由 close（）引发的任何异常。 / p>

如果是这样，我不得不怀疑我会不会使用它。我肯定不想要 throw 由 close（）抛出的异常，调用者不知道做到这一点并且尝试包装另一个尝试只是为了处理 close（）至少不会看起来很优雅。

编辑：我想我不小心问了两个问题，其中一个是重复的

问题1.我必须声明我的方法从 close（）方法中抛出异常，将try-with-resources包装在另一个尝试中？ （在建议的副本中未回答）

问题2.有没有办法静默关闭资源？ （显然是一个重复的，所以我把这个句子拿出来了，希望这个问题令人满意的是唯一的。）

解决方案

报价来自：

所以，基本上，包装器已经实现了

Please correct me if this is wrong: In Java 7's try-with-resources statement, any exceptions thrown by the resource's close() method must be either declared as thrown by my method or I must wrap the whole try in another try which catches any exceptions thrown by close().

If so, I have to wonder if I will make much use of it. I certainly don't want to throw the exceptions thrown by close(), the caller won't know what to do with that. And a try wrapping another try just to handle close() would not look very elegant, to me at least.

EDIT: I think I accidentally asked two questions, one of which was a duplicate.

Question 1. Do I have to declare that my method throws the exception from the close() method or wrap the try-with-resources in another try? (Not answered in proposed duplicate.)

Question 2. Is there a way to close the resource silently? (Clearly a duplicate, so I am taking that sentence out of the question. Hopefully this makes the question satisfactorily unique.)

解决方案

Quote from Java Language Specification ($14.20.3.2):

So, basically, wrapper is already implemented

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