问题描述
我已经尝试了许多解决方案,并提出了一个很好的解决方案,但仍然收到错误。我正在编辑我的整个问题。我正在尝试使用friendly_id gem创建Friendly URL。
在我的项目中第一个用户需要用devise注册。
Devise将通过
我想让user.name成为Friendly_id候选人。我在我的个人资料模型中尝试过以下代码: -
class Profile< ActiveRecord :: Base
extends FriendlyId
friendly_id:user_name,use::slugged
def user_name
user.name
end
但它是错误
现在提交用户表单后。
请说明可能的解决方案,解释。
我的User.rb看起来像
require'open-uri'
class User< ActiveRecord :: Base
paginates_per 10
验证:name,presence:true,length:{maximum:200}
范围:by_name, - > )do
join(:profile).where('lower(name)LIKE?',%#{name.downcase}%)
end
委托:年龄,::city,:region,:country,to::profile
has_one:profile,depend::destroy
acceptance_nested_attributes_for:profile
def self.new_with_session(params,session)
session_params = {'profile_attributes'=> {}}
provider = session ['devise.provider']
如果提供者&& data = session [devise。#{provider}]
session_params ['name'] = data [:name] if data [:name]
session_params ['email'] = data [:email ]如果data [:email]
session_params ['profile_attributes'] =
{头像:data [:image]}如果data [:image]
end
params.deep_merge!(session_params)
super.tap do | user |
如果auth = Authorization.find_from_session(session,provider)
user.authorizations<<< auth
end
end
end
def password_required?
超级&& registered_manually?
end
def registered_manually?
encrypted_password.present?
end
end
而我的profile.rb看起来像
class Profile< ActiveRecord :: Base
extends FriendlyId
friendly_id user.name,use::slugged
belongs_to:user
acceptable_nested_attributes_for:user
验证:网站,allow_blank:true,uri:true
def website =(url_str)
如果url_str.present?
url_str =http://#{url_str},除非url_str [/ ^ https?/]
write_attribute:website,url_str
end
end
end
我认为问题在这里:
请求参数
{action=>new,controller=>users / registrations}
请建议可能的解决方案和说明。
和用户/注册:
class Users :: RegistrationsController< Devise :: RegistrationsController
layout'land'
def create
params [:user] [:profile_attributes] .delete(:place)
end
protected
def after_sign_up_path_for(resource)
welcome_path
end
end
我在个人资料控制器中创建用户
def load_profile
@ profile = Profile.friendly.find(params [:id])
if!@profile || @ profile.user.blocked_users.include?(current_user)
redirect_to home_path
else
@user = @ profile.user
end
end
@Rodrigo帮助我找出错误是由于Friendly_id无法创建与用户实例的链接的错误。
此行出现错误:
friendly_id user.name,use::slugged
变量用户不' t存在于配置文件
类范围内。你应该使用这样的东西:
friendly_id:user_name,use::slugged
def user_name
user.name
end
I have tried many solution and came up with good one but still getting error. I am editing my whole question.
I am trying to create Friendly URL with friendly_id gem.In my project First user need to signup with devise.Devise will pass some information to profile model with
I want to make user.name to be Friendly_id candidate. I have tried following code in my Profile model:-
class Profile < ActiveRecord::Base
extend FriendlyId
friendly_id :user_name , use: :slugged
def user_name
user.name
end
But it is giving error
now After submitting user form.
Please suggest possible solution with explanation.
My User.rb looks like
require 'open-uri'
class User < ActiveRecord::Base
paginates_per 10
validates :name , presence: true, length: { maximum: 200 }
scope :by_name, ->(name) do
joins(:profile).where('lower(name) LIKE ?', "%#{name.downcase}%")
end
delegate :age, :city, :region, :country, to: :profile
has_one :profile, dependent: :destroy
accepts_nested_attributes_for :profile
def self.new_with_session(params, session)
session_params = { 'profile_attributes' => {} }
provider = session['devise.provider']
if provider && data = session["devise.#{provider}"]
session_params['name'] = data[:name] if data[:name]
session_params['email'] = data[:email] if data[:email]
session_params['profile_attributes'] =
{ avatar: data[:image] } if data[:image]
end
params.deep_merge!(session_params)
super.tap do |user|
if auth = Authorization.find_from_session(session, provider)
user.authorizations << auth
end
end
end
def password_required?
super && registered_manually?
end
def registered_manually?
encrypted_password.present?
end
end
And my profile.rb looks like
class Profile < ActiveRecord::Base
extend FriendlyId
friendly_id user.name, use: :slugged
belongs_to :user
accepts_nested_attributes_for :user
validates :website, allow_blank: true, uri: true
def website=(url_str)
if url_str.present?
url_str = "http://#{url_str}" unless url_str[/^https?/]
write_attribute :website, url_str
end
end
end
I think Problem is here:
Request parameters
{"action"=>"new", "controller"=>"users/registrations"}
Please suggest possible solution and explanation.
And users/registration:
class Users::RegistrationsController < Devise::RegistrationsController
layout 'land'
def create
params[:user][:profile_attributes].delete(:place)
end
protected
def after_sign_up_path_for(resource)
welcome_path
end
end
I am creating user in profile controller
def load_profile
@profile = Profile.friendly.find(params[:id])
if !@profile || @profile.user.blocked_users.include?(current_user)
redirect_to home_path
else
@user = @profile.user
end
end
@Rodrigo helped me find out error that error is due to Friendly_id can't create link with user instance.
There is an error on this line:
friendly_id user.name, use: :slugged
The variable user doesn't exists at Profile
class scope. You should use something like this:
friendly_id :user_name, use: :slugged
def user_name
user.name
end
这篇关于NoMethodError在/ undefined方法`name'为nil:NilClass的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!