问题描述
MutationRecord.addedNodes返回带有检测到的节点的NodeList，该节点已添加到我的文档中.当我使用obj.appendChild()方法时，mutationObserver会检测到它，并以节点列表[node]的形式返回MutationRecord.addedNodes中的这个ONE节点.当我在循环中使用.appendChild()时，mutationObserver会触发与循环次数相同的次数.
MutationRecord.addedNodes returns NodeList with nodes detected as added in my document. When I use obj.appendChild() method, mutationObserver detects it and returns this ONE node in MutationRecord.addedNodes as nodelist [node]. When I use .appendChild() in loop, mutationObserver fires as many times as the number of loops amounts.
我只是想知道是否有任何情况时mutationOvserver会检测到同时添加的多个节点并触发ONCE并将MutationRecord.addedNodes中的那些节点作为一个节点列表[node，node，node，...]返回吗?/p>
I'm just wondering if there is any case when mutationOvserver will detect more than one node added simultaneously and fire ONCE and return those nodes in MutationRecord.addedNodes as ONE nodelist [node,node,node,...]?
推荐答案
由规范一个 appendChild 对应于一个单节点 addedNodes 数组.
Judging by the spec one appendChild corresponds to a single-node addedNodes array.
addedNodes 通常在初始页面加载期间包含许多节点，并且自然地，如果通过 insertAdjacentHTML 或 document的一次操作在js代码中插入了许多节点.write 或 .innerHTML 或 .outerHTML 或 DocumentFragment ，其中包含许多节点.
addedNodes usually contains many nodes during the initial page load and, naturally, if many nodes were inserted by js code in one operation via insertAdjacentHTML, or document.write, or .innerHTML, or .outerHTML, or DocumentFragment with many nodes.
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