有没有办法用#define替换长名称空间?

问题描述

假设我有一个很长的名称空间，我不想一直输入.但是我也不想使用using namespace ....我可以为此使用#define吗?

Suppose I have a very long namespace, which I don't want to type in all the time. But I don't want to use using namespace ... either. Can I use #define for this?

示例:

#define glm::quat glm::gtc::quaternion

class Camera
{
protected:
    glm::quat m_mRotation;
};

我不想使用using，因为我认为glm ::部分也将消失.所以我想保留glm部分，而不要保留整个gtc :: quaternion部分.现在尝试此操作时，出现以下错误:

I don't want to use the using, because the glm:: part will be gone as well, I think. So I would like to keep the glm part, but not the totally long gtc::quaternion part. When I try this now, I get the following error:

推荐答案

您不需要定义，请使用名称空间别名:

you don't need a define, use a namespace alias:

namespace glm_quat = glm::gtc::quaternion::quat;

或者如果您希望别名确实在glm命名空间中，请将其放在此处:

or if you want the alias to be really in the glm namespace, put it there:

namespace glm {
  namespace quat = gtc::quaternion::quat;
}

这篇关于有没有办法用#define替换长名称空间?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！