从django模板传递变量来查看

问题描述

我正在使用django 1.7构建我的第一个网站，并且很难弄清楚如何将变量从点击传递给视图。我的GET也是空的。

我的模板有一张带有Facebook帐户ID的表格，点击时应显示用户管理员的Facebook页面列表。

我的模板：

  {％for accountAccount in accountlist％} 
< TR> 
< td>< a href ={％url'INI：fbpages'％}> {{SocialAccount.uid}}< / a>< / td> 
< td> {{SocialAccount.extra_data.first_name}}< / td> 
< td> {{SocialAccount.extra_data.last_name}}< / td> 
< td> {{SocialAccount.extra_data.email}}< / td> 
< / tr> 
 {％endfor％} 
  

和我的观点：

  def fbpages（request，fbuser）：
 djuser = request.user.id 
 context = RequestContext（request）
 fbuser = 1234634 
 pagelist = facebook.pages（request，djuser，fbuser）
 blocks = {'title'：'Facebook Pages'，
'pagelist'：pagelist} 
 return render （请求，倡议/ ListFBPages.html，块）
  

如果我放URL中的ID，但我不想在URL中公开一个页面/用户标识。我觉得有一个简单的解决方案，但我还没有想到这一点。

感谢您的帮助。

解决方案

您只能从4种不同的方法从模板发送数据到Django视图。在您的情况下，如果您不想要URL中的信息，您可能只能使用选项1和4.

1。发布

所以你会提交一个有价值的表单。

 ＃你可以通过
 request.POST.get（'value'）在你的views.py中检索你的代码
  

2。查询参数

所以你会传递// localhost：8000 /？id = 123

 ＃您可以通过
 request.GET.get（'id'）
   
 
 
  3。从URL（例如，请参阅） 
 
 
 
所以你会传递// localhost：8000/12 / results / 
 ＃urls.py 
 urlpatterns = patterns（
 ... 
 url（r'^（？P< question_id> \d +）/ results / $'，views.results，name ='results'），
 ... 
）
  
视图... 
 ＃views.py 
＃检索（question_id）
 def detail（请求，question_id）：
 ... 
返回HttpResponse（blahblah）
  
的 4。会话（通过cookie） 
 
 
 
使用会话的缺点是您不得不将其传递给视图或更早地设置。
 
 
 
  
 ＃views.py 
＃设置会话变量
 request.session ['uid'] = 123456 
 
＃检索会话变量
 var = request.session.get ['uid'] 
  
 
I'm building my first site with django 1.7 and am having a hard time figuring out how to pass a variable from a click to a view. My GET is also empty.
My template has a table with Facebook Account IDs, when clicked should show a list of Facebook pages that user Admins.
My template:
{% for SocialAccount in accountlist %}
   <tr>
      <td><a href="{% url 'INI:fbpages' %}">{{ SocialAccount.uid }}</a></td>
      <td>{{ SocialAccount.extra_data.first_name }}</td>
      <td>{{ SocialAccount.extra_data.last_name }}</td>
      <td>{{ SocialAccount.extra_data.email }}</td>
   </tr>
{% endfor %}
and my view:
def fbpages(request, fbuser):
    djuser = request.user.id
    context = RequestContext(request)
    fbuser = 1234634
    pagelist = facebook.pages(request, djuser, fbuser)
    blocks = {'title': 'Facebook Pages',
          'pagelist': pagelist}
    return render(request, "initiative/ListFBPages.html", blocks)
I could do this easily if I put the ID in the URL but I don't want to expose a page/user ID in the url. I feel like there's an easy solution but I haven't figured it out.
Thanks for you help.
 解决方案 
You can only send data to Django views from the template in 4 different methods. In your case you will probably only be able to use option 1 and 4 if you don't want the information in the URL.
1. Post
So you would submit a form with value.
    # You can retrieve your code in your views.py via
    request.POST.get('value')
2. Query Parameters
So you would pass //localhost:8000/?id=123
    # You can retrieve your code in your views.py via
    request.GET.get('id')
3. From the URL (See here for example)
So you would pass //localhost:8000/12/results/
    # urls.py
    urlpatterns = patterns(
        ...
        url(r'^(?P<question_id>\d+)/results/$', views.results, name='results'),
        ...
    )
and in your views...
    # views.py
    # To retrieve (question_id)
    def detail(request, question_id):
        ...
        return HttpResponse("blahblah")
4. Session (via cookie)
Downside of using session is you would have had to pass it to the view or set it earlier.
https://docs.djangoproject.com/en/1.7/topics/http/sessions/
    # views.py
    # Set the session variable
    request.session['uid'] = 123456

    # Retrieve the session variable
    var = request.session.get['uid']
                        
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