本文介绍了是否有必要在@interface中声明ivars以匹配属性?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我对这两个代码段感到困惑:
I'm confused by these two code segments:
首先:
//.h
@interface Student : NSObject {
}
@property (nonautomic, copy) NSString *name;
@property (nonautomic, retain) NSNumber *age;
@end
//.m
@implementation Student
@synthesize name;
@synthesize age;
@end
第二名:
//.h
@interface Student : NSObject {
NSString *name; // <<============ difference
NSNumber *age; // <<============ difference
}
@property (nonautomic, copy) NSString *name;
@property (nonautomic, retain) NSNumber *age;
@end
//.m
@implementation Student
@synthesize name;
@synthesize age;
@end
这两项都可以。那么是否有必要在 {}
中声明变量?
Both of these can work. So is it necessary to declare variables in the {}
?
推荐答案
从现代运行时(x86_64和ARM6 ...和iOS模拟器)开始,您不再需要声明合成的ivars。在第一个例子中,@synthesize正在为你添加实例变量。
Starting with the modern runtime (x86_64 and ARM6...and iOS Simulator) you no longer need to declare synthesized ivars. In the first example @synthesize is adding the instance variable for you.
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