问题描述
我发现 MongoDB 聚合框架非常强大 - 将对象展平似乎是一个不错的选择.我的架构在一个名为 materials
的数组中使用了一个子对象数组.material
的数量是可变的,但特定字段 category
在数组中的对象中将是唯一的.我想使用聚合框架来展平结构并根据 category
字段的值动态重命名字段.我找不到使用 $project
和 $cond
来完成此任务的简单方法.有办法吗?
I am finding the MongoDB aggregation framework to be extremely powerful - it seems like a good option to flatten out an object. My schema uses a an array of sub objects in an array called materials
. The number of materials
is variable, but a specific field category
will be unique across objects in the array. I would like to use the aggregation framework to flatten the structure and dynamically rename the fields based on the value of the category
field. I could not find an easy way to accomplish this using a $project
along with $cond
. Is there a way?
材质对象数组的原因是为了允许简单的搜索:
The reason for the array of material objects is to allow simple searching:
例如{ 'materials.name' : 'XYZ' }
拉回XYZ"所在的任何文档.找到了.
e.g. { 'materials.name' : 'XYZ' }
pulls back any document where "XYZ" is found.
例如前后文档
{
"_id" : ObjectId("123456"),
"materials" : [
{
"name" : "XYZ",
"type" : "Red",
...
"category" : "A"
},
{
"name" : "ZYX",
"type" : "Blue",
...
"category" : "B"
}]
}
到
{
"material_A_name" : "XYZ",
"material_A_type" : "Red",
...
"material_B_name" : "ZYX",
"material_B_type" : "Blue",
...
}
推荐答案
jira 中有一个类似这样的请求 https://jira.mongodb.org/browse/SERVER-5947 - 如果您想拥有此功能,请投票.
There is a request for something like this in jira https://jira.mongodb.org/browse/SERVER-5947 - vote it up if you would like to have this feature.
与此同时,如果您预先知道键的可能值是什么(即类别"的所有唯一值),并且我有一些示例代码,则有一种解决方法在我的博客上.
Meanwhile, there is a work-around if you know up front what the possible values of the keys will be (i.e. all unique values of "category") and I have some sample code on it on my blog.
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