在Firebase中，有没有办法获取节点的子节点数而不加载所有的节点数据？

问题描述

您可以通过

firebase_node.once('value', function(snapshot) { alert('Count: ' + snapshot.numChildren()); });

但我相信这会从服务器获取该节点的整个子树。对于巨大的列表，这似乎RAM和延迟密集。有没有办法获取计数（和/或一个子名字的列表）而不获取整个事情？

But I believe this fetches the entire sub-tree of that node from the server. For huge lists, that seems RAM and latency intensive. Is there a way of getting the count (and/or a list of child names) without fetching the whole thing?

推荐答案

您提供的代码段确实加载了整组数据，然后在客户端计数，这对于大量数据来说可能非常慢。

The code snippet you gave does indeed load the entire set of data and then counts it client-side, which can be very slow for large amounts of data.

Firebase不目前有一种方法来计算孩子没有加载数据，但我们计划添加它。

Firebase doesn't currently have a way to count children without loading data, but we do plan to add it.

现在，一个解决方案是保持一个计数器的孩子数并在每次添加新孩子时更新它。您可以使用事务对项目进行计数，例如在此代码中跟踪upvodes：

For now, one solution would be to maintain a counter of the number of children and update it every time you add a new child. You could use a transaction to count items, like in this code tracking upvodes:

var upvotesRef = new Firebase('https://docs-examples.firebaseio.com/android/saving-data/fireblog/posts/-JRHTHaIs-jNPLXOQivY/upvotes');
upvotesRef.transaction(function (current_value) {
  return (current_value || 0) + 1;
});

有关详情，请参阅

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