处理多个异常时共享Python代码

问题描述

我编写了一个程序，该程序需要处理可能引发多个异常的函数.对于每个捕获到的异常，我都有一些专门处理它的代码.

I've written a program that needs to deal with a function that can throw multiple exceptions. For each exception I catch I have some code that will handle it specifically.

但是，无论捕获到哪个异常，我也都有一些我想运行的代码.我当前的解决方案是一个handle_exception()函数，该函数从每个except块中调用.

However, I also have some code I want to run no matter which exception was caught. My current solution is a handle_exception() function which is called from each except block.

try:
    throw_multiple_exceptions()
except FirstException as excep:
    handle_first_exception()
    handle_exception()
except SecondException as excep:
    handle_second_exception()
    handle_exception()

是否有更好的方法可以做到这一点?我希望代码看起来像这样:

Is there a better way to do this?I would like the code to look like this:

try:
    throw_multiple_exceptions()
except FirstException as excep:
    handle_first_exception()
except SecondException as excep:
    handle_second_exception()
except Exception as excep:
    handle_exception()

推荐答案

PEP 0443 ?它非常棒且具有很好的可扩展性，因为您要做的就是编写代码并注册新的处理程序

how about PEP 0443? its awesome, and very scalable because all you have to do is code and register new handlers

from functools import singledispatch
@singledispatch
def handle_specific_exception(e): # got an exception we don't handle
    pass

@handle_specific_exception.register(Exception1)
def _(e):
    # handle exception 1

@handle_specific_exception.register(Exception2)
def _(e):
    # handle exception 2

try:
    throw_multiple_exceptions()
except Exception as e:
    handle_specific_exception(e)
    handle_exception()

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