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问题描述
我有一个看起来像这样的熊猫数据透视表:
I have a pandas pivot table that looks a little like this:
C bar foo
A B
one A -1.154627 -0.243234
three A -1.327977 0.243234
B 1.327977 -0.079051
C -0.832506 1.327977
two A 1.327977 -0.128534
B 0.835120 1.327977
C 1.327977 0.838040
我希望能够过滤掉A列少于B列2行的行,以便上面的表格可以过滤A =一:
I'd like to be able to filter out rows where column A has fewer than 2 rows in column B, so that the table above would filter A = one:
C bar foo
A B
three A -1.327977 0.243234
B 1.327977 -0.079051
C -0.832506 1.327977
two A 1.327977 -0.128534
B 0.835120 1.327977
C 1.327977 0.838040
我该怎么做?
推荐答案
一行:
In [64]: df[df.groupby(level=0).bar.transform(lambda x: len(x) >= 2).astype('bool')]
Out[64]:
bar foo
two A 0.944908 0.701687
B -0.204075 0.713141
C 0.730844 -0.022302
three A 1.263489 -1.382653
B 0.124444 0.907667
C -2.407691 -0.773040
在即将发布的熊猫(11.1)中,新的 方法可以更快,更直观地实现这一目标:
In the upcoming release of pandas (11.1), the new filter
method achieves this faster and more intuitively:
In [65]: df.groupby(level=0).filter(lambda x: len(x['bar']) >= 2)
Out[65]:
bar foo
three A 1.263489 -1.382653
B 0.124444 0.907667
C -2.407691 -0.773040
two A 0.944908 0.701687
B -0.204075 0.713141
C 0.730844 -0.022302
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