问题描述
初始化方法中定义的 int 变量，使其值为 0 ，直到计算出特定值为 int 。什么可以将 char 的值初始化为？
char retChar =''; 这给出了错误，如果我初始化为 -1 ，则表示字符过多。
You initialize an int variable defined within a method to have a value of 0 until you compute specific values for the int. What can one initialize char values to?char retChar = '';this gives an error and if I initialise to -1 it says too many characters.
推荐答案
通常，对于本地变量，我会尽可能地初始化它们。我很少需要虚拟值。但是，如果您执行，您可以使用您喜欢的任何值 - 如果您确定在阅读之前要分配值，则不会有任何区别。
Typically for local variables I initialize them as late as I can. It's rare that I need a "dummy" value. However, if you do, you can use any value you like - it won't make any difference, if you're sure you're going to assign a value before reading it.
如果你想要 char 相当于0，它只是Unicode 0，可以写成
If you want the char equivalent of 0, it's just Unicode 0, which can be written as
char c = '\0';
这也是实例（或静态）变量的默认值输入 char 。
That's also the default value for an instance (or static) variable of type char.
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